字符串"Sat May 28 18:02:30 +0800 2011"如何转化为日期格式

[bian8021]

我有一个字符串为："Sat May 28 18:02:30 +0800 2011"

想用datatime.parse转化日期格式，老是出错，可能是格式问题。大家有没有什么好办法。

[大蛮]

截取字符串 一截一截转

[bian8021]

截太麻烦了，而且遇到Sat这个还要判断，还May之类的

[andyalex]

转的，基本思路就这样，.net里没有直接转这样字符串的，

 public string Stime2string(string str)
        {
            string[] strtime = str.Split(' ');
            int y, d, m;
            y = Convert.ToInt32(strtime[5]);
            d = Convert.ToInt32(strtime[2]);
            switch (strtime[1])
            {
                case "Jan": m = 1; break;
                case "Feb": m = 2; break;
                case "Mar": m = 3; break;
                case "Apr": m = 4; break;
                case "May": m = 5; break;
                case "June": m = 6; break;
                case "July": m = 7; break;
                case "Aug": m = 8; break;
                case "Sept": m = 9; break;
                case "Oct": m = 10; break;
                case "Nov": m = 11; break;
                case "Dec": m = 12; break;
                default: m = 1; break;
            }
            DateTime t = new DateTime(y, m, d);
            return t.ToString("yyyy-MM-dd");
        }

[bian8021]

查到办法了：
DateTime dt = DateTime.ParseExact(status.created_at, "ddd MMM dd HH:mm:ss zzz yyyy", new System.Globalization.CultureInfo("en-US"));