【求助】学完线程，写了个死锁的线程，但老报错，为什么？

[h43857892]

public class Test5 implements Runnable {

int flag;
static Object o1,o2 = new Object();

public void run() {

if(flag==1){
synchronized (o1) {
System.out.println("拿到o1");
synchronized (o2) {
System.out.println("也拿到o2");
}
}
}

if(flag==2){
synchronized (o2) {
System.out.println("拿到o2");
synchronized (o1) {
System.out.println("也拿到o1");
}
}
}

}

/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Test5 t1 = new Test5();
t1.flag = 1;
Test5 t2 = new Test5();
t2.flag = 2;
Thread r1 = new Thread(t1);
Thread r2 = new Thread(t2);

r1.start();
r2.start();

}

}

[Jaya1989]

static Object o1,o2 = new Object();
这样只初始化了o2，o1没有初始化。

public class Test5 implements Runnable {

    int flag;
    static Object o1 = new Object(), o2 = new Object();

    public void run() {

	if (flag == 1) {
	    synchronized (o1) {
		System.out.println("拿到o1");
		synchronized (o2) {
		    System.out.println("也拿到o2");
		}
	    }
	}

	if (flag == 2) {
	    synchronized (o2) {
		System.out.println("拿到o2");
		synchronized (o1) {
		    System.out.println("也拿到o1");
		}
	    }
	}

    }

    /**
     * @param args
     */
    public static void main(String[] args) {
	// TODO Auto-generated method stub
	Test5 t1 = new Test5();
	t1.flag = 1;
	Test5 t2 = new Test5();
	t2.flag = 2;
	Thread r1 = new Thread(t1);
	Thread r2 = new Thread(t2);

	r1.start();
	r2.start();

    }

}

[Flycutter]

顶楼上，而且最好要sleep一下，才容易看出死锁的效果，否则很难看到效果的

[一剑风寒起]

static不懂用不要乱用啊！你在这里使用static没有意义(staic主用于资源共享，你在这里想共享什么?)；
去掉static就可以了!死锁问题是各自拿不到所须的监视器发生的！为了保证死锁发生，应该廷长一下时间，增长线程切换的概率！