多行记录，如何返回时间最靠前的。

[gong_max]

一张表T1，字段如下
(
id decimal(18,0),
name varchar(10),
recordTime datetime
)
表中有多条记录，除了最后一个时间字段，其他的都相同如下
1 'zhangsan' 2011-01-01
1 'zhangsan' 2010-09-14

我如何只取时间最靠近当前的一条记录？？

[pengxuan]

select * from T1 a where not exists(select 1 from T1 where name=a.name and recordTime>a.recordTime)

[水族杰纶]

row_number()over(partition by order by )

[-晴天]

select * from t1 a where not exists(select 1 from t1 where abs(datediff(mi,recordtime,getdate()))<abs(datediff(mi,a.recordtime,getdate()))

[jmx123456789]

select top 1 * from t1 order by recordTime desc

[Felixzhaowenzhong]

和 当前日期做 差，取差值最小的

[Felixzhaowenzhong]

select DATEDIFF(ms,GETDATE(),getdate()+1)---毫秒
select DATEDIFF(day,GETDATE(),getdate()+1)---天
select DATEDIFF(HOUR,GETDATE(),getdate()+1)---小时
select DATEDIFF(Minute,GETDATE(),getdate()+1)---分钟
select DATEDIFF(Second,GETDATE(),getdate()+1)---秒

[勿勿]

select * from T1 a where not exists(select 1 from T1 where name=a.name and recordTime>a.recordTime)

[gong_max]

[Quote=引用 1 楼 pengxuan 的回复:]

SQL code

select * from T1 a where not exists(select 1 from T1 where name=a.name and recordTime>a.recordTime)
[/Quote]
可以，感谢。