如何给数组的元素进行排序？

[EdwardLong]

ids = ["s1","s2","s3","s4","s5","s6","s7","s8","s9","s10"]
我想通过一些方法对这个数组的元素进行任意的排序

例如把 ids[1]---ds[3] 放置与 ids[4] 的后面，得到结果如下
ids = ["s1","s5","s2","s3","s4","s6","s7","s8","s9","s10"]

请问有什么好的方法？

[EdwardLong]

自己搞掂，贴出主要代码？
请大家看看这思路有没有不妥的地方。
红色文字部分为数组重组
var rowList = ["s1","s2","s3","s4","s5","s6","s7","s8","s9","s10"]
rowList=rowList== null?(parentgrid.getAllRowIds()).split(","):rowList;//设置全局行ID列表值；
var newIdsArr = new Array();
var target = this.action=="up"? parseInt(this.result.target.index)-1:parseInt(this.result.target.index);
var beginIndex = parseInt(this.result.source.index) -1;//开始索引[grid.rowid = dom索引 -1]
var rowspanval = parseInt(this.result.source.rowspan);//合并行数
var endIndex = rowspanval + beginIndex;
var idsArr = rowList;
for(var i=0; i< idsArr.length; i++)
{
if(i==target)
{
for(var n=beginIndex; n<endIndex; n++ )
{
newIdsArr.push(idsArr[n]);
}
}
if(i < beginIndex || i> endIndex-1) {
newIdsArr.push(idsArr[i]);
}
}
rowList = newIdsArr;

[p2227]

你的任意也太任意了吧，只能针对每一种模式编个程序

http://www.w3school.com.cn/js/jsref_obj_array.asp

[EdwardLong]

如果在数组内部不能进行元素排序，那么根据移动范围和目标位置，重新配置一个新的数组，那应该可以吧

[南老頭]

兄弟，你这叫数组重组，不叫数组排序， 自己个看着放吧

[峭沙]

	Array.prototype.transsituation = function(oIndex, tIndex, elemNum){
		elemNum = elemNum || 1;
		var arrbuf = this.splice(oIndex, elemNum);
		this.splice(tIndex, 0 , arrbuf);
	}
	var arr = [0,1,2,3,4,5,6,7,8,9];
	arr.transsituation(1, 3, 2);
	alert(arr);

第一个参数是要移动的元素的起始位置，第二个参数是要移动的目标位置，都是从0开始计算，第三个元素是要移动的元素个数(可选，默认为1)

[SK猫]

5楼是我想到的，6楼的没看懂

[meizz]

var ids = ["s1","s2","s3","s4","s5","s6","s7","s8","s9","s10"];
// 编写排序规则
function mm(a, b){
	var a1 = +(a.substr(1));
	a1 == 5 && (a1 = 1.5);

	var b1 = +(b.substr(1));
	b1 == 5 && (b1 = 1.5);

	return a1 > b1 ? 1 : (a1 < b1 ? -1 : 0);
}
ids.sort(mm);
alert(ids);