郁闷的问题，急需解决 Could not find action or result

[zgr1231]

我在用jquery调用后台action方法时，居然报Could not find action or result
后台action方法

/**
	 * 获取所有请假单
	 */
	public void getAllLeave(){
		try {
			List list=leaveService.findByUserLeave(1);
			String[] keys=new String[]{"leaveId","user","day","applyTime","status","content"};
			JSONArray ja=JsonUtils.listToJsonArray(list, keys);
			JSONObject jo=new JSONObject();
			jo.put("root", ja);
			jo.put("total",list.size());
			jo.put("success", true);
			System.out.println(jo.toString());
			outJson(jo.toString());;
		} catch (SqlOperationException e) {
			outJsonFailure(e.getMessage());
			e.printStackTrace();
		}
	}

struts 配置

<action name="leaveAction" class="leaveAction"></action>

applicationContext配置

<bean id="leaveService" class="com.airimposition.is.server.sm.db.impl.LeaveServiceImpl">
		<property name="leaveDao" ref="leaveDao"/>
		<property name="jbpmTemplate" ref="jbpmTemplate"></property>
	</bean>
<bean id="leaveAction" class="com.airimposition.is.action.sm.db.LeaveAction" scope="prototype">
		<property name="leaveService" ref="leaveService"></property>
	</bean>