数据字典中值的排序

[风一样的大叔]

Dictionary<string,int> NewLengths = new Dictionary<string,int>();
            for (int n = 0; n < tableArray.Length - 1; n++)
            {
                for (int u = 0; u < TableLengths.Count; u++)
                {
                    if (TableLengths[u].Name == tableArray[n])
                    {
                        NewLengths.Add(TableLengths[u].Name,TableLengths[u].Length);
                    }
                }
            }

NewLengths的值为:
"aaa",3
"ddd",4
"fff",2
"rrr",1

我现在要将这个数据字典按照value值排序,即为
"rrr",1
"fff",2
"aaa",3
"ddd",4
最后的保存形式可以为数据字典,不行的话为List也行啊,求怎么排序呢

[快乐大法师]

http://hi.baidu.com/pctonc/blog/item/6db3a2fb4b7e8c8d59ee90db.html

[杨友山]

            string[] itemList =new string[] { "x=10", "y=5", "k=4", "r=9" };
            int flag = 1;

            int i, j;

            int itemCount = itemList.Length;

            string itemTemp;

            for (i = 1; i < itemCount && flag == 1; i++)
            {
                flag = 0;

                for (j = 0; j < itemCount - i; j++)
                {
                    string itemfore = itemList[j];

                    int countfore = Convert.ToInt32(itemfore.Substring(itemfore.IndexOf('=') + 1, itemfore.Length - (itemfore.IndexOf('=') + 1)));

                    string itemback = itemList[j + 1];

                    int countback = Convert.ToInt32(itemback.Substring(itemback.IndexOf('=') + 1, itemback.Length - (itemback.IndexOf('=') + 1)));

                    if (countfore < countback)
                    {
                        flag = 1;

                        itemTemp = itemList[j];

                        itemList[j] = itemList[j + 1];

                        itemList[j + 1] = itemTemp;
                    }
                }
            }
            return itemList;
        }

这是我曾经用到的一个排序。

[stonespace]

放到List里，用List.Sort排序，效率最高，

[风一样的大叔]

[Quote=引用 1 楼 kkxxllasasas 的回复:]
http://hi.baidu.com/pctonc/blog/item/6db3a2fb4b7e8c8d59ee90db.html
[/Quote]试了下.貌似不行啊,没变化

[vrhero]

字典无序，现排即可....

NewLengths.OrderBy(o=>o.Value)

如果集合很大，你应该用其他数据结构...

[红皮书徒有虚名]

class Program
    {
        static int keySelector(KeyValuePair<string, int> entry)
        {
            return entry.Value;
        }

        static void Main()
        {
            Dictionary<string, int> vals = new Dictionary<string, int>();
            vals.Add("asp.net", 3);
            vals.Add("vb.net", 2);
            vals.Add("html5", 1);

            IOrderedEnumerable<KeyValuePair<string, int>> result = vals.OrderBy(keySelector);

            foreach (var item in result)
                Console.WriteLine("{0}:{1}", item.Key, item.Value);

        }
    }

[风一样的大叔]

问题解决了

 var list = (from d in Lengths orderby d.Value ascending select d).ToList();//对数据字典进行排序

这样默认是按升序排序的