php中构造函数对变量的引用怎么没有值啊?
本人初学php,下面的程序输出结果,$name都为空。各位知道咋回事吗?
<?php
class base
{
private $name ;
function __construct ($name2)
{
$name=$name2;
echo "base(__construct):my name:".$name ."\n";
}
function __destruct ()
{
echo "base(__destruct):"."\n";
}
}
class TestClass extends base
{
private $name ="Son";
function __construct ()
{
parent::__construct($name);
echo "TestClass(__construct):my name:".$name."\n";
}
function __destruct ()
{
echo "TestClass(__destruct):"."\n";
}
}
$testClass=new TestClass();
?>