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分享字符串制表符分解求助
读取文本里面的内容以后,原本打算使用 strtok 函数来分解字符串结果才发现 举例(假设用 ","来代替制表符tab) : CString st= "a1,a2,,a4"; 这种情况的时候 strtok函数会忽略掉 中间没有内容的地方 直接就被忽略了变成: a1 a2 a4 而我要的是把中间的没有内容的地方也要保留 变成 a1 a2 a4 或者空缺的地方用其他表示也行 a1 a2 NULL a4 请高手帮忙 本人是新手 麻烦高手用代码说明
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程序员小迷 2012-01-25
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这个你需要单独判断了
RLib 2012-01-24
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System::String st = "a1,a2,,a4";
System::StringArray ss = st.Split(",");
ss就是分割后的结果
System::StringArray ss = st.Split(",");
ss就是分割后的结果
Eleven 2012-01-20
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CString str = _T("a1,a2,,a4");
LPCTSTR lpszToken = _T(",");
CString strText(str);
int nFlag = -1;
CString tmp(_T(""));
while(TRUE)
{
nFlag = strText.Find(lpszToken);
if(-1 == nFlag)
{
if(!strText.IsEmpty())
tmp = strText;
break;
}
tmp = strText.Left(nFlag);
AfxMessageBox(tmp);
strText = strText.Right(strText.GetLength() - nFlag - 1);
}
AfxMessageBox(tmp);
qixing1115 2012-01-19
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看看这个怎么样
结果为：
ca
bdfbwa
fef
b
c
dfs
请按任意键继续. . .
char *strtok_he(const char *src, char *demial,unsigned int n)
{
char map[32];
int count;
int i = 0;
char* str = strdup(src);
char* ctrl = demial;
char *str_org;
if (src == NULL || demial == NULL)
{
return NULL;
}
for (count =0; count <32; count++)
{
map[count] = 0;
}
while (*ctrl)
{
map[*ctrl >> 3] |= (1 << (*ctrl & 7));
++ctrl;
}
str_org = str;
for (;*str; str++)
{
if ( map[*str >> 3] & (1 << (*str & 7)))
{
if (i == n)
{
*str++ = '\0';
break;
}
++i;
str_org = str+1;
}
}
if (i<n)
{
return NULL;
}
return str_org;
}
int main()
{
char buf[100] = "ca,bdfbwa,fef,,b,c,dfs";
char *p = NULL;
int i = 0;
p = strtok_he(buf,",",0);
while (p != NULL)
{
cout << p << endl;
i++;
p = strtok_he(buf,",",i);
}
}结果为：
ca
bdfbwa
fef
b
c
dfs
请按任意键继续. . .
赵4老师 2012-01-19
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#include <stdio.h>
#include <string.h>
char string[80];
char seps1[3];
char seps2[3];
char *token;
char *zzstrtok (
char *string,
const char *control1,//连续出现时视为中间夹空token
const char *control2 //连续出现时视为中间无空token
)
{
unsigned char *str;
const unsigned char *ctrl1 = control1;
const unsigned char *ctrl2 = control2;
unsigned char map1[32],map2[32];
static char *nextoken;
static char flag=0;
unsigned char c;
int L;
memset(map1,0,32);
memset(map2,0,32);
do {
map1[*ctrl1 >> 3] |= (1 << (*ctrl1 & 7));
} while (*ctrl1++);
do {
map2[*ctrl2 >> 3] |= (1 << (*ctrl2 & 7));
} while (*ctrl2++);
if (string) {
if (control2[0]) {
L=strlen(string);
while (1) {
c=string[L-1];
if (map2[c >> 3] & (1 << (c & 7))) {
L--;
string[L]=0;
} else break;
}
}
if (control1[0]) {
L=strlen(string);
c=string[L-1];
if (map1[c >> 3] & (1 << (c & 7))) {
string[L]=control1[0];
string[L+1]=0;
}
}
str=string;
}
else str=nextoken;
string=str;
while (1) {
if (0==flag) {
if (!*str) break;
if (map1[*str >> 3] & (1 << (*str & 7))) {
*str=0;
str++;
break;
} else if (map2[*str >> 3] & (1 << (*str & 7))) {
string++;
str++;
} else {
flag=1;
str++;
}
} else if (1==flag) {
if (!*str) break;
if (map1[*str >> 3] & (1 << (*str & 7))) {
*str=0;
str++;
flag=0;
break;
} else if (map2[*str >> 3] & (1 << (*str & 7))) {
*str=0;
str++;
flag=2;
break;
} else str++;
} else {//2==flag
if (!*str) return NULL;
if (map1[*str >> 3] & (1 << (*str & 7))) {
str++;
string=str;
flag=0;
} else if (map2[*str >> 3] & (1 << (*str & 7))) {
str++;
string=str;
} else {
string=str;
str++;
flag=1;
}
}
}
nextoken=str;
if (string==str) return NULL;
else return string;
}
void main()
{
strcpy(string,"A \tstring\t\tof ,,tokens\n\nand some more tokens, ");
strcpy(seps1,",\n");strcpy(seps2," \t");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,"1234| LIYI|China | 010 |201110260000|OK");
strcpy(seps1,"|");strcpy(seps2," ");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,"1234|LIYI||010|201110260000|OK");
strcpy(seps1,"");strcpy(seps2,"|");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,"1234|LIYI||010|201110260000|OK");
strcpy(seps1,"|");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,"a");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,"a,b");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,"a,,b");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,",a");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,"a,");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,",a,,b");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,",,a,,b,,");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,",");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,",,");
strcpy(seps1,",");strcpy(seps2,"");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
strcpy(string,",,,");
strcpy(seps1,",");strcpy(seps2," ");
printf("\n[%s]\nTokens:\n",string);
token=zzstrtok(string,seps1,seps2);
while (token!=NULL) {
printf(" <%s>",token);
token=zzstrtok(NULL,seps1,seps2);
}
}
//
//[A string of ,,tokens
//
//and some more tokens,]
//Tokens:
// <A>, <string>, <of>, <>, <tokens>, <>, <and>, <some>, <more>, <tokens>, <>,
//[1234| LIYI|China | 010 |201110260000|OK]
//Tokens:
// <1234>, <LIYI>, <China>, <010>, <201110260000>, <OK>,
//[1234|LIYI||010|201110260000|OK]
//Tokens:
// <1234>, <LIYI>, <010>, <201110260000>, <OK>,
//[1234|LIYI||010|201110260000|OK]
//Tokens:
// <1234>, <LIYI>, <>, <010>, <201110260000>, <OK>,
//[a]
//Tokens:
// <a>,
//[a,b]
//Tokens:
// <a>, <b>,
//[a,,b]
//Tokens:
// <a>, <>, <b>,
//[,a]
//Tokens:
// <>, <a>,
//[a,]
//Tokens:
// <a>, <>,
//[,a,,b]
//Tokens:
// <>, <a>, <>, <b>,
//[,,a,,b,,]
//Tokens:
// <>, <>, <a>, <>, <b>, <>, <>,
//[,]
//Tokens:
// <>, <>,
//[,,]
//Tokens:
// <>, <>, <>,
//[,,,]
//Tokens:
// <>, <>, <>, <>,
qixing1115 2012-01-19
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http://topic.csdn.net/u/20081022/20/2766c46d-6ed3-4567-b0d9-bb9c4fc79236.html
要是不行就自己写分割函数吧，也不难写
要是不行就自己写分割函数吧，也不难写
「已注销」 2012-01-19
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另外说明: 我需要的是把这组字符串分解以后 各自保存在字符串变量里面 比方说
Cstring str1 = "a1";
Cstring str1 = "a2";
Cstring str1 = "";
Cstring str1 = "a4";
Cstring str1 = "a1";
Cstring str1 = "a2";
Cstring str1 = "";
Cstring str1 = "a4";
