如何判断循环集合里面的重复项

[lizlqq5]

IList<VIWWHUSERDUTY> list = manager.GetAllVIWWHUSERDUTY(user.PKID.ToString());
for (int i = 0; i < list.Count; i++)
{
this.txtWHMode.Text += list[i].NAME_1 + " ";
}

如何获取NAME_1不相等

[ViewStates]

list.Distinct(...)

继承IEqualityComparer<VIWWHUSERDUTY>,实现接口方法即可

[酷儿]

继承IEqualityComparer<VIWWHUSERDUTY>,实现接口方法即可

[lizlqq5]

合并for循环的重复项 大侠们 怎么做啊

[宝_爸]

想1楼说的参考这里的代码

public class Product
{
    public string Name { get; set; }
    public int Code { get; set; }
}

// Custom comparer for the Product class
class ProductComparer : IEqualityComparer<Product>
{
    // Products are equal if their names and product numbers are equal.
    public bool Equals(Product x, Product y)
    {

        //Check whether the compared objects reference the same data.
        if (Object.ReferenceEquals(x, y)) return true;

        //Check whether any of the compared objects is null.
        if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null))
            return false;

        //Check whether the products' properties are equal.
        return x.Code == y.Code && x.Name == y.Name;
    }

    // If Equals() returns true for a pair of objects 
    // then GetHashCode() must return the same value for these objects.

    public int GetHashCode(Product product)
    {
        //Check whether the object is null
        if (Object.ReferenceEquals(product, null)) return 0;

        //Get hash code for the Name field if it is not null.
        int hashProductName = product.Name == null ? 0 : product.Name.GetHashCode();

        //Get hash code for the Code field.
        int hashProductCode = product.Code.GetHashCode();

        //Calculate the hash code for the product.
        return hashProductName ^ hashProductCode;
    }

}


Product[] products = { new Product { Name = "apple", Code = 9 }, 
                       new Product { Name = "orange", Code = 4 }, 
                       new Product { Name = "apple", Code = 9 }, 
                       new Product { Name = "lemon", Code = 12 } };

//Exclude duplicates.

IEnumerable<Product> noduplicates =
    products.Distinct(new ProductComparer());

foreach (var product in noduplicates)
    Console.WriteLine(product.Name + " " + product.Code);

/*
    This code produces the following output:
    apple 9 
    orange 4
    lemon 12
*/

你可以修改Equals的实现，只判断Name是否相等
代码来自:
http://msdn.microsoft.com/en-us/library/bb338049.aspx

[宝_爸]

或者

List<string> tempList = new List<string>(list.Count);
for (int i = 0; i < list.Count; i++)
{
if (tempList.Contain(list[i].NAME_1)
continue;
tempList.Add(list[i].NAME_1);
this.txtWHMode.Text += list[i].NAME_1 + " ";
}

代码没有编译验证，只用于阐述思路。

[lizlqq5]

[Quote=引用 5 楼 findcaiyzh 的回复:]

或者

List<string> tempList = new List<string>(list.Count);
for (int i = 0; i < list.Count; i++)
{
if (tempList.Contain(list[i].NAME_1)
continue;
tempList.Add(list[i].NAME_1);
……
[/Quote]

List<string> tempList = new List<string>(list.Count);
声明这个集合我没有看懂是什么意思
错误 6 参数“1”: 无法从“string”转换为“Model.VIWWHUSERDUTY” G:\开发工作\仓库\WarehouseSystem\WarehouseSystem\Model\MasterForm.aspx.cs 83 38 WarehouseSystem

[lizlqq5]

[Quote=引用 1 楼 viewstates 的回复:]

list.Distinct(...)

继承IEqualityComparer<VIWWHUSERDUTY>,实现接口方法即可
[/Quote]

这个怎么继承 你能告诉我吗 ，我没有玩过