求SQL先按大于当前时间升序排序，再按小于当前时间降序排序

[zyciis33]

现在有一个会议表
现在要求列出会议列表
先按还没有到会议时间升序排序，
再按已过会议时间的倒序排序

这个SQL怎么写

谢谢

[sweetbbs]

select * from tb order by case when meetingtime>=getdate() then 0 else 1 end,abs(datediff(ss,getdate(),meetingtime)) asc

[dawugui]

[Quote=引用楼主 zyciis33 的回复:]
现在有一个会议表
现在要求列出会议列表
先按还没有到会议时间升序排序，
再按已过会议时间的倒序排序

这个SQL怎么写

谢谢
[/Quote]

select * from (select top 100 percent * from tb where dt <= '会议时间' order by dt) m
union all
select * from (select top 100 percent * from tb where dt > '会议时间' order by dt desc) n

[开着拖拉机泡妞]

select *from(rselect *,case when date <getdate() then 0 else 1 end as a from t)b order by a,(case when a =1 then date end),(case when a=0 then date end)deas

[开着拖拉机泡妞]

select *from(rselect *,case when date <getdate() then 0 else 1 end as a from t)b order by a,(case when a =1 then date end),(case when a=0 then date end)deas

[开着拖拉机泡妞]

给测试数据

[开着拖拉机泡妞]

-->生成测试数据:
GO
IF OBJECT_ID('TBL')IS NOT NULL
DROP TABLE TBL
GO
CREATE TABLE TBL(
日期 DATE,
备注 VARCHAR(100)
)
GO
INSERT TBL
SELECT '2012-03-02','B' UNION ALL
SELECT '2012-03-05','C' UNION ALL
SELECT '2012-03-06','D' UNION ALL
SELECT '2012-03-07','E' UNION ALL
SELECT '2012-03-09','F' UNION ALL
SELECT '2012-03-11','G' UNION ALL
SELECT '2012-03-12','H' UNION ALL
SELECT '2012-03-13','I' UNION ALL
SELECT '2012-03-15','J' UNION ALL
SELECT '2012-03-19','K' UNION ALL
SELECT '2012-03-20','L'


--不使用union all
;with t
as(
select *,case when 日期>=getdate() then 1 else 0 end as A
from tbl
)

select 日期,备注 from t
order by a,(case when a=1 then 日期 end),
(case when a=0 then 日期 end) desc

/*
日期	备注
2012-03-09	F
2012-03-07	E
2012-03-06	D
2012-03-05	C
2012-03-02	B
2012-03-11	G
2012-03-12	H
2012-03-13	I
2012-03-15	J
2012-03-19	K
2012-03-20	L
*/

[开着拖拉机泡妞]

select * from tbl where 会议时间>getdate() order by 会议时间 asc
union all
select * from tbl where 会议时间<getdate() order by 会议时间 desc

[开着拖拉机泡妞]

GO
IF OBJECT_ID('TBL')IS NOT NULL
DROP TABLE TBL
GO
CREATE TABLE TBL(
日期 DATE,
备注 VARCHAR(100)
)
GO
INSERT TBL
SELECT '2012-03-02','B' UNION ALL
SELECT '2012-03-05','C' UNION ALL
SELECT '2012-03-06','D' UNION ALL
SELECT '2012-03-07','E' UNION ALL
SELECT '2012-03-09','F' UNION ALL
SELECT '2012-03-11','G' UNION ALL
SELECT '2012-03-12','H' UNION ALL
SELECT '2012-03-13','I' UNION ALL
SELECT '2012-03-15','J' UNION ALL
SELECT '2012-03-19','K' UNION ALL
SELECT '2012-03-20','L'

go
create table #tbl(
日期 DATE,
备注 VARCHAR(100),
num int
)
go
insert #tbl
select *,ROW_NUMBER()over(order by 日期 asc) as num from tbl where 日期>=GETDATE()
union all
select *,ROW_NUMBER()over(order by 日期 desc) as num from tbl where 日期<GETDATE()

select 日期,备注 from #tbl



/*
日期	备注
2012-03-11	G
2012-03-12	H
2012-03-13	I
2012-03-15	J
2012-03-19	K
2012-03-20	L
2012-03-09	F
2012-03-07	E
2012-03-06	D
2012-03-05	C
2012-03-02	B
*/

[zyciis33]

谢谢
但能不能不要用
union all
方式
因为我要做分页

而且我用的分页是一个通用的方法
有没有
Select * From MyMeeting Order By ????
这种写法，直接写OrderBy的
谢谢

[开着拖拉机泡妞]

好像还可以用case when 实现，电脑环境关了，明天吧