VC中如何将byte数组转为char*

[lang14]

比如 byte[3]={0x12,0x45,0x78};
我是想让他转化为：char *p; p=124578; 请问如何解决？？

[lang14]

谢谢各位

[小马喝水]

char temp[6];
for (i = 0; 1 = 2; i++)
temp[i] = itoa(byte[i],&temp[i*2], 16)

[小马喝水]

[Quote=引用 1 楼 zhaoze87 的回复:]

char temp[6];
for (i = 0; 1 = 2; i++)
temp[i] = itoa(byte[i],&temp[i*2], 16)
[/Quote]
写得有点小问题
char temp[6];
for (i = 0; 1 = 2; i++)
itoa(byte[i],&temp[i*2], 16)

[lgstudyvc]

memcpy或者楼上的for

[lang14]

[Quote=引用 3 楼 lgstudyvc 的回复:]
memcpy或者楼上的for
[/Quote]
memcpy得到的是乱码，

[gameslq]

16进制转字符串

unsigned char * HexToStr(unsigned char *szOutStr,size_t szlen,unsigned char *hex,size_t size)
{
	unsigned char ch,shiftch;
	unsigned char * src = hex;
	unsigned char * des = szOutStr;

	if ( szOutStr == NULL || hex == NULL ) 
		return NULL;
	//buffer size
	if ( (szlen - 1) < size * 2)
		return NULL;
	while ( size-- > 0 )
	{
		ch = *src++;
		shiftch = ch >>4;
		if ( shiftch >= 0x0 && shiftch <= 0x09 )
			*des++ = shiftch + '0';
		if ( shiftch >= 0x0a && shiftch <= 0x0f )
			*des++ = shiftch + '1';
		shiftch = ch & 0x0f;
		if ( shiftch >= 0x0 && shiftch <= 0x09 )
			*des++ = shiftch + '0';
		if ( shiftch >= 0x0a && shiftch <= 0x0f )
			*des++ = shiftch + '1';
		
	}
	
	*des = 0;
	return szOutStr;
}

[MagicFuzzX]

byte其实就是unsigned char

[gameslq]

*des++ = shiftch + '1';
改为
*des++ = shiftch + 0x57;或
*des++ = shiftch + 0x37;

[shn521]

学习了，原来这么转化

[FounderSG]

[Quote=引用 8 楼 shn521 的回复:]

学习了，原来这么转化
[/Quote]
学习了