replace的使用

[lanita]

表一：conv_line
conv_line_oid error_msg
1001 client %s1 not facility %s2
1002 client %s1 not facility %s2

表二
facility_group
facility_group_oid client facility conv_line_oid
2001 clientA facilityA 1001
2002 clientB facilityB 1002


要把
conv_line_oid error_msg
1001 client %s1 not facility %s2
1002 client %s1 not facility %s2

更新为
conv_line_oid error_msg
1001 client clientA not facility facilityA
1002 client clientB not facility facilityB


有何实现办法吗？

[lxyzxq2008]

楼主的不仅仅是replace问题，还有update from的问题，
在oracle中没有update from，这个语法是sql server的，
虽然可以通过子查询的方式来实现update from的功能：
但是如果把replace也加进去，好像就有问题了，也就是说replace中不能写select语句吧

[lanita]

麻烦各位高手啦，谢谢

[youshang444]

SELECT A.CONV_LINE_OID,
REPLACE(REPLACE(A.ERROR_MSG, '%s1', B.CLIENT), '%s2', B.fACILITY)
FROM CONV_LINE A, FACILITY_GROUP B
WHERE A.CONV_LINE_OID = B.CONV_LINE_OID;

[开着拖拉机泡妞]

go
create table conv_line(
conv_line_oid varchar(4),
error_msg varchar(50) 
)
go
insert conv_line
select '1001','client %s1 not facility %s2' union all
select '1002','client %s1 not facility %s2'

go
create table facility_group(
facility_group_oid varchar(4),
client varchar(10),
facility varchar(10),
conv_line_oid varchar(4)
)
go
insert facility_group
select '2001','clientA','facilityA','1001' union all
select '2002','clientB','facilityB','1002'


update conv_line
set error_msg=replace(REPLACE(error_msg,'%s1',client),'%s2',facility)
from facility_group a where a.conv_line_oid=conv_line.conv_line_oid

select * from conv_line

/*
conv_line_oid	error_msg
1001	client clientA not facility facilityA
1002	client clientB not facility facilityB
*/

MSSQL语法，楼主修改数据类型即可

[lanita]

啊，原来可以这样，用REGEXP_REPLACE 可能会更方便呢。。

[lanita]

嗯，所以现在只能先select replace后再update了。。。

[coolkisses]

update + select ，这倒不是什么问题。
建议再看一下这两张表，是否存在 一对多的关系，否则，需要微调一下SQL。