如何在sql中查询某个字段不同值分别取一定数量.

[温柔哥]

SELECT * FROM `表名` WHERE 类型="甲" ORDER BY rand() limit 0,3;
SELECT * FROM `表名` WHERE 类型="乙" ORDER BY rand() limit 0,1;
我想要的就是 取4条记录出来,其中 类型=甲有3条 类型=乙有1条
如何用一条sql语句执行.
望高手给出结果,

[开着拖拉机泡妞]

select top 3 * from tracy where AZWZ='1330采面'
union all
select top 1* from tracy where AZWZ='223水仓'
/*
AZWZ	PJZ	ZDZ	BCSJ
1330采面	0.33	0.34	2010-01-01 00:00:00.000
1330采面	0.33	0.34	2010-01-01 00:05:00.000
1330采面	0.33	0.34	2010-01-01 00:00:00.000
223水仓	0.33	0.34	2010-01-01 00:00:00.000
*/

感觉不用union all一条语句实现有难度

[温柔哥]

查询不出来阿..报错 #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '3 * FROM `musicData` WHERE musicType="joke" union all SELECT TOP 1 * FROM `music' at line 1

[开着拖拉机泡妞]

[Quote=引用 2 楼 tongfei8608 的回复:]

查询不出来阿..报错 #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '3 * FROM `musicData` WHERE musicType=&quo……
[/Quote]

汗，Mysql的，你来错地方了。去对应的板块问问吧

[温柔哥]

我这是mysql 不支持top阿

[温柔哥]

那你能帮帮我解决下这个问题不

[ACMAIN_CHM]

(SELECT * FROM `表名` WHERE 类型="甲" ORDER BY rand() limit 0,3)
union all
(SELECT * FROM `表名`  WHERE 类型="乙" ORDER BY rand() limit 0,1);