缓存清不了，不知道为什么。

[wasdeq7521]

#include<iostream.h>
#include<stdlib.h>
#include<time.h>
#include<conio.h>
int main(){
int a,char b;
srand((unsigned)time(0));
do{
for(int i=0;i<1;i++){
double ran_num=rand()%10;
do{
cout<<"please enter a number between 1 to 10.\n";
cin.clear();
cin.sync();
cin>>a;
if(a==0){
cout<<"data type error!\n";
b='y';
continue;}
if(a<=0||a>=10){
cout<<"input a number between 1 to 10!\n";
b='y';
continue;}
if(a!=ran_num&&a>ran_num){
cout<<"please input a lesser number\n";}
if(a!=ran_num&&a<ran_num){
cout<<"please input a lager number\n";}
}while(a!=ran_num);
cout<<"Gongratulation!\n";
}
do{
cout<<"\nContinue(yes or no)?\n";
b=getche();
}while(b!='y'&&b!='n');
}while(b=='y');
}


各位大哥可以复制下来，到vc6中运行下试试。由于我才学c++，有很多问题啊~~~~
这个是个简单的猜数游戏，我想控制不能输入字母，但一旦输入字母就会出现无限循环的情况，应该是缓存没清,但我写了cin.clear();cin.sync();的呀，真不知道为什么了~~~~~；还有就是当猜对时，要输入“y”，才会出现 “Gongratulation!”，然后就立马重复游戏了......这个顺序不对啊，应该是出现“Gongratulation!”再问“Continue(yes or no)?”，输入“y”之后才继续游戏啊......
麻烦大家帮帮忙吧，我真不知道是哪出问题了~~~~~谢谢拉~~~~~

[W170532934]

int main(){
	int a,char b;
	srand((unsigned)time(0));
	do{
			double ran_num=rand()%10;
			do{
				cout<<"please enter a number between 1 to 10.\n";  
				
				cin>>a;
				if (cin.bad())
				{
					cin.clear();
					cin.sync();
					continue;
				} 
				else
				{
					if(a==0){
						cout<<"data type error!\n";
						b='y';
						continue;
					}
					if(a<=0||a>=10){
						cout<<"input a number between 1 to 10!\n";
						b='y';
						continue;
					}
					if(a!=ran_num&&a>ran_num){
						cout<<"please input a lesser number\n";}
					if(a!=ran_num&&a<ran_num){
						cout<<"please input a lager number\n";}
				}
			}while(a!=ran_num);
			cout<<"Gongratulation!\n";
		do{
			cout<<"\nContinue(yes or no)?\n";
			b=getch();
		}while(b!='y'&&b!='n');
	}while(b=='y');
}

出错了再清除。

[风云争霸]

你这个嵌套循环太多了 很容易出错的，

#include<iostream.h>
#include<stdlib.h>
#include<time.h>
#include<stdio.h>
#include<conio.h>
void main()
{ unsigned int a;
char b;
srand((unsigned)time(0));
double ran_num=rand()%10;
do{
b='c'; //将b赋值一个非Y/N
cout<<"please enter a number between 1 to 10.\n";
cin>>a;
if(a==0)
cout<<"data type error!\n";
if(a>=10)
cout<<"input a number between 1 to 10!\n";
if(a!=ran_num&&a>ran_num){
cout<<"please input a lesser number\n";}
if(a!=ran_num&&a<ran_num){
cout<<"please input a lager number\n";}
if (a==ran_num)
cout<<"Gongratulation!\n";

cout<<"\nContinue(yes or no)?\n";
cin>>b;}
while(b=='y');
}

[wasdeq7521]

谢谢啦，我试过了，有用的~~~~