查找json数据

[jy02409187]

[
	{"id": 123, "con": "gggdfg"},
	{"id": 124, "con": "jgjjghj"},
	{"id": 125, "con": "khkhk"},
	{"id": 126, "con": "ggtyuryrty"},
	{"id": 127, "con": "dfsfsf"}
]

例如上面，我要查找id=125的con的内容应该怎么写啊

[jy02409187]

其实我要实现的是

<ul>
<li id="123"></li>
<li id="124"></li>
<li id="125"></li>
<li id="126"></li>
<li id="127"></li>
</ul>

把JSON里面的数据准备写到li里面

var json = [
{ "id": 123, "con": "gggdfg" },
{ "id": 124, "con": "jgjjghj" },
{ "id": 125, "con": "khkhk" },
{ "id": 126, "con": "ggtyuryrty" },
{ "id": 127, "con": "dfsfsf" }
];

如果用这个就很好写

var num = json.length;
for(var i=0; i<num; i++){
if( json[i].id == li.eq(i).attr("id")){
li.eq(i).html(json[i].con);
}
}

但有个问题就是当JSON里面的ID顺序和LI的ID顺序不一致时就会出错

var json = [
{ "id": 123, "con": "gggdfg" },
{ "id": 126, "con": "jgjjghj" },
{ "id": 124, "con": "khkhk" },
{ "id": 126, "con": "ggtyuryrty" },
{ "id": 125, "con": "dfsfsf" }
];

[prototyper]

最好是你后台返回（或者在现有返回下转换成）这样格式的HASH TABLE：json = {123 : "gggdfg", 126 : "jgjjghj"。。。。。}。

[prototyper]

HASH数据FOR IN索引效率高THAN ARRAY。

[jy02409187]

$("li[id="+id+"]").html(json[i].con);

原来是脑子抽了，这样就可以

[fangkaifang]

遍历json不就好了嘛 遍历json的方法百度一把就ok了

[xuzuning]

遍历呀

<script>
d = [
    {"id": 123, "con": "gggdfg"},
    {"id": 124, "con": "jgjjghj"},
    {"id": 125, "con": "khkhk"},
    {"id": 126, "con": "ggtyuryrty"},
    {"id": 127, "con": "dfsfsf"}
];

for(i=0; i<(d.length); i++)
  if(d[i].id == 125) alert(d[i].con);
</script>

[ohmygirl]

function getCon(array){
for(var i = 0;i<array.length;i++){
var obj = array[i];
if(obj.id == "125"){
return obj.con;
}
}
return null;
}
var array = [ {"id": 123, "con": "gggdfg"}, {"id": 124, "con": "jgjjghj"}, {"id": 125, "con": "khkhk"}, {"id": 126, "con": "ggtyuryrty"}, {"id": 127, "con": "dfsfsf"} ]
var result = getCon(array);
alert(result);

[hellNo]

	var t2 = [
    {"id": 123, "con": "gggdfg"},
    {"id": 124, "con": "jgjjghj"},
    {"id": 125, "con": "khkhk"},
    {"id": 126, "con": "ggtyuryrty"},
    {"id": 127, "con": "dfsfsf"}
];
var myobj=eval(t2);
for(var i=0;i<myobj.length;i++){
   alert(myobj[i].id);
   alert(myobj[i].con);
}

[wzhiyuan]

如果你的结构就是这样的两个元素，而且每个ID都不重复，为了以后随时取用某个ID的CON，我建议可以加这个数据存储到一个关联数组中

      var arr1 = [
    { "id": 123, "con": "gggdfg" },
    { "id": 124, "con": "jgjjghj" },
    { "id": 125, "con": "khkhk" },
    { "id": 126, "con": "ggtyuryrty" },
    { "id": 127, "con": "dfsfsf" }
];
    var arr2 = new Array;
    for (var i = 0; i < arr1.length; i++) {
        arr2[arr1[i]["id"]] = arr1[i]["con"];
    }
    alert(arr2["125"]);

[liminjun88]

我现在就是存到li里面，但是如何解决递归查找呀?