求c++矩阵相加和相减

[征服全世界Orz]

1.编程实现矩阵相加和相减。（提示：定义矩阵类，数据成员为数组，重载+，-两个运算符）。
例如：
123 213 336
231 + 132 = 363
321 321 633

[yuxi1989]

有一本书，叫《常用算法程序集（C++语言描述）》，徐士良编著。里边第一章。

[cbzjzsb123]

有一本书，叫《常用算法程序集（C++语言描述）》，徐士良编著。里边第一章。

[GYTAnonymous]

正好我又写过。。

给你参考参考。。我多了个重载*号，，还有 = << >> ;，

头文件

#ifndef MATRIX_H
#define MATRIX_H

class Matrix
{
public:
	Matrix( int =0, int =0);
	Matrix( double** , int , int  );
	Matrix( const Matrix& );
	~Matrix();
	void Set( double**, int, int );
	friend Matrix operator+ ( const Matrix&, const Matrix& );
	friend Matrix operator- ( const Matrix&, const Matrix& );
	friend Matrix operator* ( const Matrix&, const Matrix& );
	Matrix& operator= ( const Matrix& );
	friend istream& operator>> ( istream&, Matrix& );
	friend ostream& operator<< ( ostream&, const Matrix& );
protected:
	double** ma;
	int length;
	int width;
};

//functions
Matrix::Matrix( int wid, int len )
{
	if( len==0 || wid==0 )
	{
		length = width = 0;
		ma = '\0';
		return ;
	}
	length = len;
	width = wid;
	ma = new double*[width];
	for( int i=0; i<width; i++ )
		ma[i] = new double[length];
}
Matrix::Matrix( double** p, int wid, int len )
{
	if( wid<=0 || len <=0 )
	{
		cout << "error !\n";
		exit(0);
	}
	Set( p, wid, len );
}
Matrix::Matrix( const Matrix& Matr )
{
	Set( Matr.ma, Matr.width, Matr.length );
}
Matrix::~Matrix()
{
	for( int i=0; i<width; i++ )
		delete[] ma[i];
	delete[] ma;
	ma = NULL;
	width = length =0;
}
void Matrix::Set( double** p, int wid, int len )
{
	length = len;
	width = wid;
	ma = new double*[width];
	for( int i=0; i<width; i++ )
	{
		ma[i] = new double[length];
		for( int j=0; j<length; j++ )
			ma[i][j] = p[i][j];
	}
}
Matrix operator+ ( const Matrix& ma1, const Matrix& ma2 )
{
	if( ma1.width != ma1.width || ma1.length != ma2.length )
	{
		cout << "error !\n";
		exit(0);
	}
	Matrix temp( ma1.width, ma1.length );
	for( int i=0; i<temp.width; i++ )
		for( int j=0; j<temp.length; j++ )
			temp.ma[i][j] = ma1.ma[i][j] + ma2.ma[i][j];
	return temp;
}
Matrix operator- ( const Matrix& ma1, const Matrix& ma2 )
{
	if( ma1.width != ma1.width || ma1.length != ma2.length )
	{
		cout << "error !\n";
		exit(0);
	}
	Matrix temp( ma1.width, ma1.length );
	for( int i=0; i<temp.width; i++ )
		for( int j=0; j<temp.length; j++ )
			temp.ma[i][j] = ma1.ma[i][j] - ma2.ma[i][j];
	return temp;
}
Matrix operator* ( const Matrix& ma1, const Matrix& ma2 )
{
	if( ma1.length != ma2.width )
	{
		cout << "error !\n";
		exit(0);
	}
	Matrix temp( ma1.width, ma2.length );
	for( int i=0; i<temp.width; i++ )
		for( int j=0; j<temp.length; j++ )
			temp.ma[i][j] = 0;
	for( int i=0; i<ma1.width; i++ )
		for( int j=0; j<ma2.length; j++ )
			for( int k=0; k<ma1.length; k++ )
				temp.ma[i][j] += ma1.ma[i][k] * ma2.ma[k][j];
	return temp;
}
Matrix& Matrix:: operator= ( const Matrix& matr )
{
	for( int i=0; i<width; i++ )
		for( int j=0; j<length; j++ )
			ma[i][j] = matr.ma[i][j];
	return *this;
}
istream& operator>> ( istream& input, Matrix& matr )
{
	for( int i=0; i<matr.width; i++ )
		for( int j=0; j<matr.length; j++ )
			cin >> matr.ma[i][j];
	cout << endl;
	return input;
}
ostream& operator<< ( ostream& output, const Matrix& matr )
{
	for( int i=0; i<matr.width; i++ )
	{
		for( int j=0; j<matr.length; j++ )
			cout << setw(8) << matr.ma[i][j] << " ";
		cout << endl;
	}
	cout << endl;
	return output;
}
#endif

主函数

#include<iostream>
#include<iomanip>
using namespace std;
#include"Matrix.h"
//main function

int main()
{
	int wid, len;
	cout << "Enter the width and length of the matrix1\n";
	cin >> wid >> len;
	Matrix ma1( wid, len );
	cout << "Enter the matrix1\n";
	cin >> ma1;

	cout << "Enter the width and length of the matrix2\n";
	cin >> wid >> len;
	Matrix ma2( wid, len );
	cout << "Enter the matrix2\n";
	cin >> ma2;
	
	cout << " ma1 + ma2 : \n" << ma1 + ma2;
	cout << " ma1 - ma2 : \n" << ma1 - ma2;
	cout << " ma1 * ma2 : \n" << ma1 * ma2;
}

[GYTAnonymous]

注意结贴啊。。。不然别人不愿意给你解决问题奥