求SQL查询.

[zl194]

SQL2000环境。
表结构如下：
列A |列B
1 |张三
1 |李四
1 |王五
1 |赵六

where 列A=1 时 想得到如下的查询结果

张三；李四；王五；赵六；

请教怎样取得。

[开着拖拉机泡妞]

declare @str varchar(2000)
set @str=''
select @str=@str+B_';' from table
select left(@str,len(@str)-1)

[昵称被占用了]

declare @name nvarchar(2000)
select @name = isnull(@name + ';','') + 列B
from 表
where 列A = 1
select @name as name

[昵称被占用了]

最后的;也要？

declare @name nvarchar(2000)
select @name = isnull(@name ,'') + 列B + ';'
from 表
where 列A = 1
select @name as name

[Mr_Nice]

if object_id('[TB]') is not null drop table [TB]
go
create table [TB] (A int,B nvarchar(4))
insert into [TB]
select 1,'张三' union all
select 1,'李四' union all
select 1,'王五' union all
select 1,'赵六'

select * from [TB]

drop function  dbo.f_str

create function dbo.f_str(@id int) returns varchar(100)
as
begin
    declare @str varchar(1000)
    set @str = ''
    select @str = @str + ';' + cast(b as varchar) from tb where a = @id
    set @str = right(@str , len(@str) - 1)
    return @str
end
go

select a,dbo.f_str(a) from TB group by a

/*
a           
----------- ----------------------------------------------------------------------------------------------------
1           张三;李四;王五;赵六

(1 行受影响)

[以学习为目的]

declare @name nvarchar(2000)
select @name = isnull(@name + ';','') + 列B
from 表
where 列A = 1
select @name as name

这个更直观