android 怎么样获取弹出窗口输入的信息

[longxuep]

public class ButtonListener implements OnClickListener {

@Override
public void onClick(View v) {
//弹出窗口事件
LayoutInflater inflater = (LayoutInflater) getApplicationContext()
.getSystemService(LAYOUT_INFLATER_SERVICE);
final View view = inflater.inflate(R.layout.style, null);

AlertDialog.Builder builder2 = new AlertDialog.Builder(
VideoClientActivity.this);

builder2.setView(view);
builder2.setTitle("添加内容").setPositiveButton("确定",
new DialogInterface.OnClickListener() {

@Override
public void onClick(DialogInterface dialog, int which) {
editTextname = (EditText) view
.findViewById(R.id.name);
editTextaddress = (EditText) view
.findViewById(R.id.address);
Log.i(TAG, editTextname.toString() + "==" + editTextaddress.toString());
try {
String name = editTextname.getText().toString();
String address = editTextaddress.getText().toString();

Video video = new Video();
video.setName(name.toString());
video.setAddress(address.toString());
dbVideoService.savesTrannces(video);
} catch (Exception e) {
e.printStackTrace();
}
dialog.cancel();
}
}).create().show();

}

}
------------------------

为什么我获取不到 editTextname ，editTextaddress的值

[j_f0001]

代码没有问题，请确定是不是真的有值，最好断点调试一下。

[sunsh1989]

没分了，借个位置问个问题：在用AChartengine画柱状图时候，怎么才能让柱状条显示显示在我想显示的位置上，即是说显示在x轴某个我想要的位置上。

[longxuep]

已经解决了........原来是接收文本框的名字写错了，总是接收不到