String数组问题

[青柠loft]

现有一个数组
String[] str = new String[]{"A","B","C","D","E","F"};

输出为： -------------------------------
| A | B | C |
-------------------------------
| D | E | F |
-------------------------------


这个线都是连在一起的，是一个两行三列表格，我这里不想往上传图片了，就随便画了一下

[qybao]

就是循环，三个元素换一次行

String[] str = new String[]{"A","B","C","D","E","F"};
String line = "-------------"; //计算好元素占的横向空间
System.out.println(line);
System.out.print("|");
for (int i = 0; i < str.length; i++) {
    System.out.printf(" %s |", str[i]);
    if ((i+1)%3 == 0) { //3个元素换一次行，并打印第一个竖线
        System.out.printf("\n%s\n%s", line, i==str.length-1 ? "" : "|");
    }
}

[jdjf020826]

[Quote=引用 2 楼 的回复:]
就是循环，三个元素换一次行

Java code
String[] str = new String[]{"A","B","C","D","E","F"};
String line = "-------------"; //计算好元素占的横向空间
System.out.println(line);
System.out.print("|");
for (int i = 0; i < ……
[/Quote]
同意

[r280881872]

晕 ，又是个不想做作业的。

[yixiwenwen]

[Quote=引用 2 楼 qybao 的回复:]

就是循环，三个元素换一次行
Java code
String[] str = new String[]{"A","B","C","D","E","F"};
String line = "-------------"; //计算好元素占的横向空间
System.out.println(line);
System.out.print("|");
for (int i = 0; i < str.l……
[/Quote]


o勒