求解类成员函数指针传递问题.

[YIRIYIQIAN]

#include<iostream>

class B;
class A
{
public:
	A(void (B::*ptr_fun)())
	{
		_ptr_fun = ptr_fun;
	}
	void fun()
	{
		_ptr_fun();  ------编译期间错误
	}
private:
	void (B::*_ptr_fun)();
};

class B
{
public:
	void fun()
	{
		obj = new A(&B::fun);
		std::cout << "B::fun()" <<std::endl;
		obj->fun();
	}
private:
	A* obj;
};

void main()
{
	B b;
	b.fun();
	system("pause");
}

[YIRIYIQIAN]

好吧 多写了个括号

[YIRIYIQIAN]

#include<iostream>

class B;
class A
{
public:
	A(void (B::*ptr_fun)(int a))
	{
		_ptr_fun = ptr_fun;
	}
	void fun()
	{
		_ptr_fun(10);        ------------还是不行
	}
private:
	void (B::*_ptr_fun)(int a);
};

class B
{
public:
	void fun(int a)
	{
		obj = new A(&B::fun);
		std::cout << "B::fun()" <<std::endl;
		obj->fun();
	}
private:
	A* obj;
};

void main()
{
	B b;
	b.fun(10);
	system("pause");
}

error C2064: 项不会计算为接受 1 个参数的函数

[天下第一好大人]

非静态类成员函数，需要用“类实例取*函数指针”调用。另外你的两个函数互相调用，会将栈压爆，我给你稍微修改了一下。

#include<iostream>

class B;
class A
{
public:
	A(void (B::*ptr_fun)(int a))
	{
		_ptr_fun = ptr_fun;
	}
	void fun()
	{
		(((B*)NULL)->*_ptr_fun)(10); // same as ((*(B*)NULL).*_ptr_fun)(10);
	}
private:
	void (B::*_ptr_fun)(int a);
};

class B
{
public:
	void fun(int a)
	{
		std::cout << "B::fun() " << a <<std::endl;
	}
	void test()
	{
		obj = new A(&B::fun);
		obj->fun();
		delete obj;
	}
private:
	A* obj;
};

void main()
{
	B b;
	b.test();
	system("pause");
}

[YIRIYIQIAN]

[Quote=引用 3 楼 的回复:]

非静态类成员函数，需要用“类实例取*函数指针”调用。另外你的两个函数互相调用，会将栈压爆，我给你稍微修改了一下。

C/C++ code

#include<iostream>

class B;
class A
{
public:
A(void (B::*ptr_fun)(int a))
{
_ptr_fun = ptr_fun;
}
vo……
[/Quote]

think you