Android的post请求问题，急！！！！！！在线等

[zuojiawei01]

public String clickInfo_Java() {

		String result = "";
		try {
			final String SERVER_URL = "http://10.0.2.2:8080/tm/AndroidAction_Android_FindByCarNumber"; // 定义需要获取的内容来源地址
			HttpPost request = new HttpPost(SERVER_URL); // 根据内容来源地址创建一个Http请求
			request.setHeader("Content-Type", "application/x-www-form-urlencoded");   

			List<NameValuePair> params = new ArrayList<NameValuePair>();
			params.add(new BasicNameValuePair("cardnumber", "123124212536")); // 添加必须的参数
			params.add(new BasicNameValuePair("x", Math.random() + "")); // 添加必须的参数
			request.setEntity(new UrlEncodedFormEntity(params, HTTP.UTF_8)); // 设置参数的编码
			// HttpResponse httpResponse = new
			// DefaultHttpClient().execute(request); // 发送请求并获取反馈
			HttpClient client = new DefaultHttpClient();

			HttpResponse httpResponse = client.execute(request);			// 解析返回的内容
			if (httpResponse.getStatusLine().getStatusCode() != 404) {
				result = EntityUtils.toString(httpResponse.getEntity());
				System.out.println(result);
			}
		} catch (Exception e) {
			Toast.makeText(this, e.getMessage().toString(), Toast.LENGTH_LONG)
					.show();
			e.printStackTrace();
		}
		return result;
	}

每次 运行到 HttpResponse httpResponse = client.execute(request); 程序就跳到了 catch 然后 窗口出现 Permission denied（没有权限）。

各位大神， 在线等， 急 ！！！！！！！

[himi_]

AndroidManifest.xml中，添加网络访问权限：

<uses-permission android:name="android.permission.INTERNET" />

[fuabcck]

兄弟，我跟你一样的情况

public class PostActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button b = (Button) findViewById(R.id.button1);
b.setOnClickListener(new OnClickListener() {

public void onClick(View v) {
HttpGet request = new HttpGet("http://10.0.2.2/android.php?name=Neeke");
try {
DefaultHttpClient df=new DefaultHttpClient();
df.getParams().setParameter(CoreConnectionPNames.CONNECTION_TIMEOUT, 10000);
df.getParams().setParameter(CoreConnectionPNames.SO_TIMEOUT, 10000);
request.addHeader("Accept-Language", "en");
HttpResponse response = df.execute(request);
/*if(response.getStatusLine().getStatusCode() == 200){
String result = EntityUtils.toString(response.getEntity());
Toast.makeText(PostActivity.this, result, Toast.LENGTH_LONG).show();
}*/

} catch (Exception e) {
Toast.makeText(PostActivity.this, "error", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
}

});
}
}




<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="podt.pack"
android:versionCode="1"
android:versionName="1.0" >
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"></uses-permission>
<uses-permission android:name="android.permission.INTERNET"></uses-permission>
<uses-sdk android:minSdkVersion="15" />
<application
android:permission="android.permission.INTERNET"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name" >
<activity
android:name=".PostActivity"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />

<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>

</manifest>

[fuabcck]

我纠结两天了，我是初学，代码是抄百度上例子的
运行到HttpResponse response = df.execute(request);，就直接跳到catch （Exception e）

[yiheng-mother]

顶啊，求高手解答，同样的问题