请教一个问题

[hdqqq]

用java准备请求一个url连接，url带查询参数。实现函数如下：

public static void open_url()
{
try {
String up_url = "http://192.168.1.60/upload/Default.aspx?id=1234567890";
java.net.URL url = new java.net.URL(up_url);
java.net.HttpURLConnection conn = (java.net.HttpURLConnection)url.openConnection();
}
catch (java.net.MalformedURLException e) {
e.printStackTrace();
}
catch (java.io.IOException e) {
e.printStackTrace();
}
}
服务端用.net 实现，现在问题是服务端取不到id和提交的参数。
想问的问题是，java这样增加参数是否正确，还是需要其他方法。

[a395885670]

InputStream inputStream = null;
		BufferedReader in = null;
		String path = null;
		try {
			path = ROOT_PATH
					+ URLEncoder.encode(MESSAGE + smsContent + PHONE
							+ phoneNumber + key, "utf-8");
			URL url;
			url = new URL(path);
			HttpURLConnection conn = (HttpURLConnection) url.openConnection();
			conn.setConnectTimeout(15000);
			conn.setReadTimeout(15000);
			conn.setRequestMethod("POST");
			conn.setRequestProperty("Content-type", "text/html");
			conn.setRequestProperty("Accept-Charset", "utf-8");
			conn.setRequestProperty("contentType", "utf-8");
			conn.setDoInput(true);
			inputStream = conn.getInputStream();
			String line;
			in = new BufferedReader(new InputStreamReader(inputStream), 1024);
			while ((line = in.readLine()) != null) {
				if (line.length() > 0) {
					Gson gson = new Gson();
					Type type = new TypeToken<SMSResult>() {
					}.getType();
					smsResult = gson.fromJson(line, type);
				}
			}
		} catch (Exception e) {
			throw e;
		} finally {
			try {
				if (null != in) {
					in.close();
				}
				if (null != inputStream) {
					inputStream.close();
				}
			} catch (Exception e) {
				throw e;
			}
		}

楼主可以参考下 需要用POST

[岁月之梦]

httpclient 例子很多哦 到网上看看

[MiceRice]

这样增加参数是可以的，不过有两个问题：
1、漏了开启动作；
2、.Net端，用的是POST方式接收参数还是GET方式？

String urlString = "http://192.168.1.60/upload/Default.aspx?id=1234567890";
URL url = new URL(urlString);
HttpURLConnection httpConn = (HttpURLConnection) url.openConnection()
httpConn.setRequestMethod("GET"); // 访问方式
httpConn.connect(); // 关键是这个动作别漏了