在线等。错误提示“no operator">>" matches these operands”怎么修改？谢谢

[tigercoco]

是一个计算一元多项式的加法数组实现，一个数组放两个多项式的系数，另一个放指数，一个数组放系数相加后的结果。指数为0输入0。大部分函数中的cin cout都有这样的问题“no operator matches these operands”谢谢

#include<iostream>
#include <stdlib.h>
#include <string>
#define degree 6

using namespace std;
class poly{

public:

void creat_coe(int);
void creat_exp(int);
void print();
void add();

};

poly coef[6], expo[6], result[6];


void poly::creat_coe(int n){
cout<<"Please enter two polynomial numbers' coefficients matching respective exponents ,if there is no such exponent in each term,please enter 0 "
<<"each number has max 3 terms"<<endl;
for(int i = 0; i < n; i++) {
cout<<"Please enter "<<i+1<<"coefficient:"; //循环输入第i个系数
cin >> coef[i]; //no operator"<<" matches these operands;
}
}
void poly::creat_exp(int n){
cout<<"Please enter two polynomial numbers' exponents matching respective coefficients from high order to low ,if there is no such exponent in each term,please enter 0 "
<<"each number has max 3 terms"<<endl;

for(int i = 0; i < n; i++) {
cout<<"Please enter "<<i+1<<"exponnet:"; //循环输入第i个指数
cin >> expo[i]; //no operator"<<" matches these operands;
}
}
void poly::add(){
for(int i=0; i<3; i++)
result[i]= coef[i] + coef[i+2];

}
void poly ::print(){
for(int i=0; i<6; i++)
cout << result[i] << expo[i]<<" "; // no operator << matches these operands

}
int main(){
poly number;
int n;
cout<<"Please enter terms of tow polynomials :" <<endl;
cin >> n;
number.creat_coe(n);
number.creat_exp(n);
number.add();
number.print();


return 0;


}

[善良超锅锅]

#include<iostream>

[tigercoco]

[Quote=引用 1 楼 的回复:]
#include<iostream>
[/Quote]加上问题依然存在。刚看了下自己写的，本身有isostream。请继续指教。

[N0bug]

[Quote=引用楼主 的回复:]
是一个计算一元多项式的加法数组实现，一个数组放两个多项式的系数，另一个放指数，一个数组放系数相加后的结果。指数为0输入0。大部分函数中的cin cout都有这样的问题“no operator matches these operands”谢谢

#include<iostream>
#include <stdlib.h>
#include <string>……
[/Quote]
expo[i];是一个poly类型 你又没有重载">>" 当然cin不进去

[tigercoco]

[Quote=引用 3 楼 的回复:]
[Quote=引用楼主 的回复:]
是一个计算一元多项式的加法数组实现，一个数组放两个多项式的系数，另一个放指数，一个数组放系数相加后的结果。指数为0输入0。大部分函数中的cin cout都有这样的问题“no operator matches these operands”谢谢

#include<iostream>
#include <stdlib.h>……
[/Quote]可否告知怎样重载呢？
谢谢...

[W170532934]

因为expo[i];是自己定义的类型，你还是在该类型里面进行操作符重载<<和>>吧

[tongzhipeng5699]

你的poly类一个属性都没有？不知道你的意图是什么，你的add里面还有加法，+也需要重载，给一个复数运算的重载的例子，你就懂了。

#include <iostream>
using namespace std;
class Complex {
public:
	Complex (int r = 0, int i = 0) : m_r (r), m_i (i) {}
	/*
	Complex operator+ (const Complex& c) const {
		return Complex (m_r + c.m_r, m_i + c.m_i);
	}
	*/
	friend Complex operator+ (const Complex& c1, const Complex& c2) {
		return Complex (c1.m_r + c2.m_r, c1.m_i + c2.m_i);
	}
	Complex operator+ (int n) {
		return Complex (m_r + n, m_i);
	}
	Complex operator- (const Complex& c) const {
		return Complex (m_r - c.m_r, m_i - c.m_i);
	}
	/*
	Complex& operator+= (const Complex& c) {
//		return *this = *this + c;
		m_r += c.m_r;
		m_i += c.m_i;
		return *this;
	}
	*/
	friend Complex& operator+= (Complex& c1, const Complex& c2) {
		return c1 = c1 + c2;
	}
	Complex& operator-= (const Complex& c) {
		return *this = *this - c;
	}
	Complex operator- (void) {
		return Complex (-m_r, -m_i);
	}
	const Complex operator++ (int) {
		Complex c = *this;
		m_r++;
		m_i++;
		return c;
	}
	Complex& operator++ (void) {
		m_r++;
		m_i++;
		return *this;
	}
	const Complex operator-- (int) {
		Complex c = *this;
		m_r--;
		m_i--;
		return c;
	}
	Complex& operator-- (void) {
		m_r--;
		m_i--;
		return *this;
	}
private:
	int m_r;
	int m_i;
	friend ostream& operator<< (ostream&, const Complex&);
	friend istream& operator>> (istream&, Complex&);
};
ostream& operator<< (ostream& os, const Complex& c) {
	os << "(" << c.m_r << "+" << c.m_i << "i)";
	return os;
}
istream& operator>> (istream& is, Complex& c) {
	return is >> c.m_r >> c.m_i;
}
int main (void) {
	Complex c1 (3, 4);
	cout << c1 << endl; // operator<<(cout,c1)
	// operator<<(cout,c1).operator<<(endl);
	Complex c2 (5, 6);
//	cin >> c2; // operator>> (cin, c2)
	Complex c3 = c1 + c2;
	// c3 = c1.operator+ (c2)
	// c3 = operator+ (c1, c2)
	cout << c1 << '+' << c2 << '=' << c3 << endl;
	cout << c3 << '-' << c2 << '=' <<c3-c2<<endl;
	Complex c4 (c1);
	(c4 += c2) += c2;
	// c4.operator+= (c2);
	// operator+= (c4, c2);
	cout << c4 << endl;
	(c4 -= c2) -= c2;
	cout << c4 << endl;
	cout << -c4 << endl;
	int n = 10;
	cout << n++ << endl; // 10
	cout << n << endl; // 11
//	(n++)++;
	int m = 10;
	cout << ++m << endl; // 11
	cout << m << endl; // 11
	++++m;
	cout << m << endl;
	cout << c1++ << endl;
	// c1.operator++ (0)
	cout << c1 << endl;
//	c1++++;
	cout << ++c2 << endl;
	cout << c2 << endl;
	++++c2;
	cout << c2 << endl;
	cout << c2+100 << endl; // c2.operator+(100)
	return 0;
}

[Quote=引用 4 楼 的回复:]
[Quote=引用 3 楼 的回复:]
[Quote=引用楼主 的回复:]
是一个计算一元多项式的加法数组实现，一个数组放两个多项式的系数，另一个放指数，一个数组放系数相加后的结果。指数为0输入0。大部分函数中的cin cout都有这样的问题“no operator matches these operands”谢谢

#include<iostream>……
[/Quote]