这个程序里有几个消费者，几个生产者??

[wzuxian2012]

代码里 只有2个线程（不算主线程在内）在运行


writer, reader内部是 用了for循环，循环次数各自是100，

这是100个消费者，100个生产者呢 还是1个生产者，1个消费者???

概念很混乱。



const int BUF_SIZE = 10; 
const int ITERS = 100; 

boost::mutex io_mutex; 

class buffer 
{ 
public: 
  typedef boost::mutex::scoped_lock scoped_lock; 
     
  buffer() 
    : p(0), c(0), full(0) 
  { 
  } 
     
  void put(int m) 
  { 
    scoped_lock lock(mutex); 
    if (full == BUF_SIZE) 
    { 
      { 
        boost::mutex::scoped_lock lock(io_mutex); 
        std::cout << 
          "Buffer is full. Waiting..." 
          << std::endl; 
      } 
      while (full == BUF_SIZE) 
        cond.wait(lock); 
    } 
    buf[p] = m; 
    p = (p+1) % BUF_SIZE; 
    ++full; 
    cond.notify_one(); 
  } 

  int get() 
  { 
    scoped_lock lk(mutex); 
    if (full == 0) 
    { 
      { 
        boost::mutex::scoped_lock  lock(io_mutex); 
        std::cout << 
          "Buffer is empty. Waiting..." 
          << std::endl; 
      } 
      while (full == 0) 
        cond.wait(lk); 
    } 
    int i = buf[c]; 
    c = (c+1) % BUF_SIZE; 
    --full; 
    cond.notify_one(); 
    return i; 
  } 
     
private: 
  boost::mutex mutex; 
  boost::condition cond; 
  unsigned int p, c, full; 
  int buf[BUF_SIZE]; 
}; 

buffer buf; 

void writer() 
{ 
  for (int n = 0; n < ITERS; ++n) 	//100次
  { 
    { 
      boost::mutex::scoped_lock  lock(io_mutex); 
      std::cout << "sending: " 
        << n << std::endl; 
    } 
    buf.put(n); 
  } 
} 

void reader() 
{ 
  for (int x = 0; x < ITERS; ++x) 	//100次
  { 
    int n = buf.get(); 
    { 
      boost::mutex::scoped_lock lock(io_mutex); 
      std::cout << "received: " 
        << n << std::endl; 
    } 
  } 
} 
     
int main(int argc, char* argv[]) 
{ 
  boost::thread thrd1(&reader); 
  boost::thread thrd2(&writer); 
  thrd1.join(); 
  thrd2.join(); 
  return 0; 
} 

[wzuxian2012]

已经找到答案了，可以结贴

[wzuxian2012]

reader, write中的循环都去掉

改成：

boost::thread w_thread[100];
boost::thread r_threa[100];

for(i=0; i<100 ;i ++)
{

w_thread[i].函数(write);
r_thread[i].函数(read);

}

会怎样？？？





[Quote=引用楼主 的回复:]
C/C++ code




代码里 只有2个线程（不算主线程在内）在运行


writer, reader内部是 用了for循环，循环次数各自是100，

这是100个消费者，100个生产者呢 还是1个生产者，1个消费者???

概念很混乱。



const int BUF_SIZE = 10;
const int ITERS = 100;

boos……
[/Quote]

[wzuxian2012]

mfc板块不讨论boost技术吗