新手请教：java调用webservice报错

[Jack0801]

我用Axis调用webservice ,报出这样一个错误： faultString: 服务器无法处理请求。 ---> 未将对象引用设置到对象的实例。
详细错误如下：
Exception in thread "main" AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server
faultSubcode:
faultString: 服务器无法处理请求。 ---> 未将对象引用设置到对象的实例。
faultActor:
faultNode:
faultDetail:
{http://xml.apache.org/axis/}stackTrace:服务器无法处理请求。 ---> 未将对象引用设置到对象的实例。
at org.apache.axis.message.SOAPFaultBuilder.createFault(SOAPFaultBuilder.java:222)
at org.apache.axis.message.SOAPFaultBuilder.endElement(SOAPFaultBuilder.java:129)
at org.apache.axis.encoding.DeserializationContext.endElement(DeserializationContext.java:1087)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.endElement(AbstractSAXParser.java:633)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanEndElement(XMLNSDocumentScannerImpl.java:719)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(XMLDocumentFragmentScannerImpl.java:1685)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:368)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:834)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:764)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:148)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1242)

import java.rmi.RemoteException;

import javax.xml.namespace.QName;
import javax.xml.rpc.ServiceException;

import org.apache.axis.client.Call;
import org.apache.axis.client.Service;

public class Test5 {
public static void main(String[] args) throws ServiceException, RemoteException{
System.getProperties().setProperty("http.proxyHost", "proxy1.bj.petrochina");
System.getProperties().setProperty("http.proxyPort", "8080");
String endPoint = "http://www.webxml.com.cn/WebServices/WeatherWebService.asmx?wsdl";

Service service = new Service();
Call call = (Call) service.createCall();
call.setTargetEndpointAddress(endPoint);
call.setReturnClass(java.lang.String[].class);

call.addParameter("theCityName", org.apache.axis.encoding.XMLType.XSD_STRING,
javax.xml.rpc.ParameterMode.IN);

call.setOperationName("getWeatherbyCityName");

call.setUseSOAPAction(true);
call.setSOAPActionURI("http://WebXml.com.cn/getWeatherbyCityName");

String[] results = (String[]) call.invoke(new Object[]{"58367"});
for(String res : results){
System.out.println("result:"+res);
}


}

}

[default_ch]

同问，怎么解决这一问题？

[玉女]

http://blog.csdn.net/a1000005a/article/details/4770052
一定要设置Action.否则服务器无法处理请求,不知道你引用的是哪个方法,所以报出未将对象引用设置到对象的实例

[有始有终1]

call.setTargetEndpointAddress(new java.net.URL("服务地址"));


call.setOperationName(new QName("命名空间","服务名称"));

[丫头嗳]

兄弟，这个问题该怎么解决？

[乐宠乐]

try{

String endPoint = "http://202.102.36.242:8080/CSB/services/ImsService";
Service service = new Service();
Call call = (Call)service.createCall();
call.setTargetEndpointAddress(new java.net.URL(endPoint));
call.setOperationName(new
QName("http://com.linkage.ims","GET_IMS_USER_INFO"));
String res = (String)call.invoke(new Object[]{"512","68284124"});
System.out.println("入参：512，68284124, 返回结果：res"+res);
}catch(Exception e){
System.out.println("出错："+e.toString());
e.printStackTrace();
}

用这个 试试