jquery选择器的一个小题目

[ThunderSei]

******************************************************************************************

<h2>Shakespeare's Plays</h2>
<table>
<tr>
<td>As You Like It</td>
<td>Comedy</td>
<td></td>
</tr>
<tr>
<td>All's Well that Ends Well</td>
<td>Comedy</td>
<td>1601</td>
</tr>
<tr>
<td>Hamlet</td>
<td>Tragedy</td>
<td>1604</td>
</tr>
<tr>
<td>Macbeth</td>
<td>Tragedy</td>
<td>1606</td>
</tr>
<tr>
<td>Romeo and Juliet</td>
<td>Tragedy</td>
<td>1595</td>
</tr>
<tr>
<td>Henry IV, Part I</td>
<td>History</td>
<td>1596</td>
</tr>
<tr>
<td>Henry V</td>
<td>History</td>
<td>1599</td>
</tr>
</table>
**************************************************************************************
上面这个表格怎么给第三个td添加一个 year 类
不能改html哦，用jquery怎么匹配啊

[独爱如风]

$('tr:fist td:last').html=year;

[夜空中苦逼的程序员]

楼主什么意思 ？不填加html 但是要改内容？？

why??? tell me why ,??
如果是1楼的那样的话 应该是 $('tr:first td:eq(2)').html(year);

[gf05011]

你的<table>没有任何属性，估计不实用

[静缘]

$('tr:first td:eq(2)').addClass(year);

[静缘]

$('tr:first td:eq(2)').addClass('year'); //字符串应该加引号

[001007009]

<h2>Shakespeare's Plays</h2>
  <table>
  <tr>
  <td>As You Like It</td>
  <td>Comedy</td>
  <td></td>
  </tr>
  <tr>
  <td>All's Well that Ends Well</td>
  <td>Comedy</td>
  <td>1601</td>
  </tr>
  <tr>
  <td>Hamlet</td>
  <td>Tragedy</td>
  <td>1604</td>
  </tr>
  <tr>
  <td>Macbeth</td>
  <td>Tragedy</td>
  <td>1606</td>
  </tr>
  <tr>
  <td>Romeo and Juliet</td>
  <td>Tragedy</td>
  <td>1595</td>
  </tr>
  <tr>
  <td>Henry IV, Part I</td>
  <td>History</td>
  <td>1596</td>
  </tr>
  <tr>
  <td>Henry V</td>
  <td>History</td>
  <td>1599</td>
  </tr>
  </table>
  <script src="http://code.jquery.com/jquery-latest.js"></script>
  <script type="text/javascript">
	$('table tr').each(function(){
		$(this).find('td:last').css({
			color: 'red'
		})
	})
  </script>