gridview 问题，解决不了，求大家帮忙...

crazynet2011 2012-07-17 01:35:29

前台



<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %>



<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head runat="server">

    <title></title>



    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js" type="text/javascript"></script>



</head>

<body>

    <form id="form1" runat="server">

    <div>

        <asp:ScriptManager ID="ScriptManager1" runat="server">

        </asp:ScriptManager>

        <%--        <asp:UpdatePanel ID="UpdatePanel1" runat="server">

            <ContentTemplate>--%>

        <asp:GridView ID="gdvData" runat="server" AutoGenerateColumns="false" OnRowEditing="gdvData_RowEditing"

            OnRowUpdating="gdvData_RowUpdating">

            <Columns>

                <asp:TemplateField HeaderText="图片">

                    <ItemTemplate>

                        xxx</ItemTemplate>

                    <EditItemTemplate>

                        <asp:FileUpload ID="FileUpload1" runat="server"></asp:FileUpload></EditItemTemplate>

                </asp:TemplateField>

                <asp:CommandField ShowEditButton="true" />

            </Columns>

        </asp:GridView>

        <%--            </ContentTemplate>

        </asp:UpdatePanel>--%>

        图片:<input type="file" runat="server" id="InputFile" style="width: 132px;" /><br />

        <asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" />

    </div>

    </form>

</body>

</html>

后台



using System;

using System.Collections.Generic;

using System.Linq;

using System.Web;

using System.Web.UI;

using System.Web.UI.WebControls;



public partial class _Default : System.Web.UI.Page

{

    private static List<string> files = new List<string> { "a", "b" };

    protected void Page_Load(object sender, EventArgs e)

    {

        if (!this.IsPostBack)

        {

            BinData();

        }

    }



    private void BinData()

    {

        gdvData.DataSource = files;

        gdvData.DataBind();

    }

    protected void gdvData_RowEditing(object sender, GridViewEditEventArgs e)

    {

        gdvData.EditIndex = e.NewEditIndex;

        BinData();

    }



    protected void gdvData_RowUpdating(object sender, GridViewUpdateEventArgs e)

    {

        Response.Write((gdvData.Rows[e.RowIndex].FindControl("FileUpload1") as FileUpload).FileName + "<br/>");



        string upFile = ((FileUpload)gdvData.Rows[e.RowIndex].FindControl("FileUpload1")).PostedFile.FileName;

        UpLoad(upFile);

    }

    protected void Button1_Click(object sender, EventArgs e)

    {

        UpLoad(InputFile.Value);

    }



    private string UpLoad(string img)

    {

        string pictureName = "";



        int idx = img.LastIndexOf('.');



        string suffx = img.Substring(idx);



        pictureName = DateTime.Now.Ticks.ToString() + suffx;



        if (img != "")

        {

            string path = Server.MapPath("Upload/Image/");



            InputFile.PostedFile.SaveAs(path + pictureName);

        }



        return pictureName;

    }

}

我有两个问题，
第一个：
如果在gridview外层添加个 UpdatePanel无刷新控件，那么在后台获取FileUpload1就会报错,这是为什么?
第二个：
在gridview外放个上传控件，然后上传图片,OK没问题，但是在gridview里的那个上传控件，我如果上传图片，那么图片就是0KB，打开提示“没有预览” 这又是为什么？
求解释？求解决？

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孟子E章 2012-07-17

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你怎么测试的不可以啊？
你可以直接拷贝下面的代码测试，不要做任何修改

<%@ Page Language="C#" EnableViewState="true" %>



<%@ Import Namespace="System.Xml" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"

"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<script runat="server">

  private static List<string> files = new List<string> { "a", "b" };

  protected void Page_Load(object sender, EventArgs e)

  {

    if (!this.IsPostBack)

    {

      BinData();

    }

  }



  private void BinData()

  {

    gdvData.DataSource = files;

    gdvData.DataBind();

  }

  protected void gdvData_RowEditing(object sender, GridViewEditEventArgs e)

  {

    gdvData.EditIndex = e.NewEditIndex;

    BinData();

  }



  protected void gdvData_RowUpdating(object sender, GridViewUpdateEventArgs e)

  {

    FileUpload upFile = gdvData.Rows[e.RowIndex].FindControl("FileUpload1") as FileUpload;

    Image Image1 = gdvData.Rows[e.RowIndex].FindControl("Image1") as Image;

    if (upFile != null)

    {

      Image1.Visible = true;

      Image1.ImageUrl = "~/" + UpLoad(upFile);

    }

    else

    {

      Response.Write("Error");

     }

  }



  private string UpLoad(FileUpload img)

  {

    string pictureName = "";

    pictureName = DateTime.Now.Ticks.ToString() + System.IO.Path.GetFileName(img.FileName);

    string path = Server.MapPath("~/" + pictureName);

    img.SaveAs(path);

    return pictureName;

  }



</script>

<html>

<head>

  <title></title>

</head>

<body>

  <form id="form1" runat="server">

  <asp:GridView ID="gdvData" runat="server" AutoGenerateColumns="false" OnRowEditing="gdvData_RowEditing"

    OnRowUpdating="gdvData_RowUpdating">

    <Columns>

      <asp:TemplateField HeaderText="图片">

        <ItemTemplate>

          xxx</ItemTemplate>

        <EditItemTemplate>

          <asp:Image ID="Image1" runat="server" Visible="false" Width="100" />

          <asp:FileUpload ID="FileUpload1" runat="server"></asp:FileUpload></EditItemTemplate>

      </asp:TemplateField>

      <asp:CommandField ShowEditButton="true" />

    </Columns>

  </asp:GridView>

  </form>

</body>

</html>

StarlightHan 2012-07-17

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FileUpload是上传控件，不是获取路径控件

crazynet2011 2012-07-17

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[Quote=引用 5 楼的回复:]

是不是没有获取到gridview里的FileUpload1的id啊？你看看数据库中有没有存入数据，要是没有的话就是

没有获取到控件的值！
[/Quote]
有，就是用gridview里的上传控件后，图片是0KB

crazynet2011 2012-07-17

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[Quote=引用 4 楼的回复:]

参数是string怎么保存文件啊
[/Quote]
参数是图片的路径，没问题啊，我改成您那样的也不行，图片还是0KB

H_Gragon 2012-07-17

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是不是没有获取到gridview里的FileUpload1的id啊？你看看数据库中有没有存入数据，要是没有的话就是

没有获取到控件的值！

孟子E章 2012-07-17

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参数是string怎么保存文件啊

crazynet2011 2012-07-17

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[Quote=引用 2 楼的回复:]

string upFile = ((FileUpload)gdvData.Rows[e.RowIndex].FindControl("FileUpload1")).PostedFile.FileName;
UpLoad(upFile);

你这里已经错误了
应该是

FileUpload upFile =gdvData.Rows[e.RowIndex].FindControl("Fi……
[/Quote]
那我把gridview的FileUpload控件改成file控件，也不行啊，参数是string就不行吗为什么要FileUpload 类型呢

孟子E章 2012-07-17

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string upFile = ((FileUpload)gdvData.Rows[e.RowIndex].FindControl("FileUpload1")).PostedFile.FileName;
UpLoad(upFile);

你这里已经错误了
应该是

FileUpload upFile =gdvData.Rows[e.RowIndex].FindControl("FileUpload1") as FileUpload;
if(upFile!=null)
UpLoad(upFile);

private string UpLoad(FileUpload img)
{
string pictureName = "";
pictureName = DateTime.Now.Ticks.ToString() + Path.GetFileName(img);

string path = Server.MapPath("~/Upload/Image/" + pictureName );
img.SaveAs(path );

return pictureName;
}

孟子E章 2012-07-17