QPixmap加载bmp图片失败？

中才德创 2012-08-03 04:39:20

m_pPixmapSource = new QPixmap();

bool bRet = m_pPixmapSource->load(strPath);

看bRet结果，发现jpg可以，bmp不行。这是为什么？

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jinjianxinxh 2012-08-13

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bool QPixmap::load ( const QString & fileName, const char * format = 0, Qt::ImageConversionFlags flags = Qt::AutoColor ) 用这个方法可以判断是否加载失败吧

中才德创 2012-08-12

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[Quote=引用 3 楼的回复:]

为何不直接 pixmap = QPixmap(path) ?
[/Quote]主要是没有返回值，失败也不知。

中才德创 2012-08-10

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一直以为是代码取矩形小方框引起的。后来发现，图片像被加密了一样，另存一次再用就可以了。

void calculateMiniRect()

{

    //矩形小方框

    int x1 = m_rectOfRedLine.left();

    int x2 = m_rectOfRedLine.right();

    int y1 = m_rectOfRedLine.top();

    int y2 = m_rectOfRedLine.bottom();

    int w = m_rectOfRedLine.width() / 2;

    int h = m_rectOfRedLine.height() / 2;



    //左上角小方块

    m_rcTopLeft.setLeft(x1);

    m_rcTopLeft.setRight(x1 + 4);

    m_rcTopLeft.setTop(y1);

    m_rcTopLeft.setBottom(y1 + 4);



    //右上角小方块

    m_rcTopRight.setLeft(x2 - 4);

    m_rcTopRight.setRight(x2);

    m_rcTopRight.setTop(y1);

    m_rcTopRight.setBottom(y1 + 4);



    //左下角小方块

    m_rcBottomLeft.setLeft(x1);

    m_rcBottomLeft.setRight(x1 + 4);

    m_rcBottomLeft.setTop(y2 - 4);

    m_rcBottomLeft.setBottom(y2);



    //右下角小方块

    m_rcBottomRight.setLeft(x2 - 4);

    m_rcBottomRight.setRight(x2);

    m_rcBottomRight.setTop(y2 - 4);

    m_rcBottomRight.setBottom(y2);



    //正左方方块

    m_rcLeftMiddle.setLeft(x1);

    m_rcLeftMiddle.setRight(x1 + 4);

    m_rcLeftMiddle.setTop(y1 + h - 2);

    m_rcLeftMiddle.setBottom(y1 + h + 2);



    //正右方方块

    m_rcRightMiddle.setLeft(x2 - 3);

    m_rcRightMiddle.setRight(x2);

    m_rcRightMiddle.setTop(y1 + h - 2);

    m_rcRightMiddle.setBottom(y1 + h + 2);



    //正上方方块

    m_rcTopMiddle.setLeft(x1 + w - 2);

    m_rcTopMiddle.setRight(x1 + w + 2);

    m_rcTopMiddle.setTop(y1);

    m_rcTopMiddle.setBottom(y1 + 4);



    //正下方方块

    m_rcBottomMiddle.setLeft(x1 + w - 2);

    m_rcBottomMiddle.setRight(x1 + w + 2);

    m_rcBottomMiddle.setTop(y2 - 4);

    m_rcBottomMiddle.setBottom(y2);

}