用单片机驱动八位数码管，用矩阵键盘控制

[never110101]

小弟想写一个程序用4*4矩阵键盘使数码管分别显示0到F

小弟写了个程序如下：
#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit dula=P2^6;
sbit wela=P2^7;
uchar code table[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e};
uchar num;
void delay(uint xms)
{
uint i,j;
for(i=xms;i>0;i--)
for(j=110;j>0;j--);
}

void display(uchar num)
{
wela=1;
P0=0x3f;
wela=0;
P0=0x00;
dula=1;
P0=table[num];
dula=0;
}

void keyscan()
{
uchar temp;
P3=0xfe;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xee: num=table[0];
break;

case 0xde: num=table[1];
break;

case 0xbe: num=table[2];
break;

case 0x7e: num=table[3];
break;
}
}
while(temp!=0xf0)
{
temp=P3;
temp=P3&0xf0;
}
display(num);

}

P3=0xfd;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xed: num=table[4];
break;

case 0xdd: num=table[5];
break;

case 0xbd: num=table[6];
break;

case 0x7d: num=table[7];
break;
}
}
while(temp!=0xf0)
{
temp=P3;
temp=P3&0xf0;
}
display(num);

}

P3=0xfb;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xeb: num=table[8];
break;

case 0xdb: num=table[9];
break;

case 0xbb: num=table[10];
break;

case 0x7b: num=table[11];
break;
}
}
while(temp!=0xf0)
{
temp=P3;
temp=P3&0xf0;
}
display(num);
}


P3=0xf7;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xe7: num=table[12];
break;

case 0xd7: num=table[13];
break;

case 0xb7: num=table[14];
break;

case 0x77: num=table[15];
break;
}
}
while(temp!=0xf0)
{
temp=P3;
temp=P3&0xf0;
}
display(num);
}

}

void main()
{
while(1)
{

keyscan();
}
}


在单片机上的效果是按了按键后，六个数码管显示的都是“8.”，小弟单片机是共阳极数码管

[nonocast]

貌似是天祥的版本

[never110101]

是的，模仿他根据自己的单片机和习惯写的，无论按那个键都是显示“8.”，请问你知道原因吗？

[霹雳华]

天祥门徒！！

[Xxxxxxx..]

简化一下吧，其实听郭天祥讲的，理解了原理，就可以自己重新再编写~自己画个矩阵来想想，印象会更深！虽然我也是看郭天祥的~加油吧！

[nonocast]

你试试这个，看看一个按键(最下排左边一个)可以不

#include <REGX52.H>

#define uint unsigned int
#define uchar unsigned char
#define true 1
#define false 0

sbit key1 = P3 ^ 4;
sbit key2 = P3 ^ 5;
sbit key3 = P3 ^ 6;
sbit key4 = P3 ^ 7;

sbit dula = P2 ^ 6;
sbit wela = P2 ^ 7;

unsigned char code table[] = {
	0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f, 0x77, 0x7c, 0x39, 0x5e, 0x79, 0x71
};

uchar numt0, num;

void delay(uint);
void display(uchar);
void init();
void keyscan();

void main(void) {
	do {
		keyscan();
		display(num);
	} while(true);
}

void init() {
	TMOD = 0x01;
	TH0 = (65536 - 45872) / 256;
	TL0 = (65535 - 45872) / 256;
	EA = 1;
	ET0 = 1;
}			

void keyscan() {
	if(key1 == 0){
		delay(10);
		if(key1 == 0){
			num = ++num % 60;
			while(!key1);
		}
	}
}

void display(uchar arg) {
	uchar shi, ge;
	shi = arg / 10;
	ge = arg % 10;

	dula = 1;
	P0 = table[shi];
	dula = 0;
	P0 = 0xff;
	wela = 1;
	P0 = 0xfe;		// 1111 1110
	wela = 0;
	delay(5);

	dula = 1;
	P0 = table[ge];
	dula = 0;
	P0 = 0xff;
	wela = 1;
	P0 = 0xfd;		// 1111 1101
	wela = 0;
	delay(5);
}

void delay(uint arg) {
	uint i, k;
	for(i = arg; i > 0; --i) {
		for(k = 110; k > 0; --k);
	}
}

[wangxiaofengq5]

理解原理后自己编一段，印象更深刻。