C++读取文件中多列数据放入二维数组问题（新学C++,望好心人指导）

[lixiaowei1234]

#include <iostream>
#include <fstream>
#include "iomanip"
#include <String>
#include <cstdlib>
#include <stdio.h>
using namespace std;
main()
{

ifstream infile;
ofstream outfile;

infile.open("G://1.txt");
float ft1;
infile>>ft1;float *p=&ft1;

if(!infile)
{
cout<<"读文件打开失败!";
exit(1);
}
cout<<"二维数组为:"<<"\n";
float data[5][4];int i,j;
if(*p!=NULL)

{
for(i=0;i<5;i++)
{
for(j=0;j<4;j++)
{

data[i][j]=*p;

cout<<data[i][j]<<" ";
p++;

}


cout<<"\n";
}


}
infile.close;
outfile.close;
return 0;
}


//理论上该出来我在G盘上的数，结果只出现一个，我想把4列数全放入一个二维数组进行计算，再写入一个文件中。。。

[shen_wei]

#include <stdio.h>

void main( void )
{
   FILE *stream;
   char list[30];
   int  i, numread, numwritten;

   /* Open file in text mode: */
   if( (stream = fopen( "fread.out", "w+t" )) != NULL )
   {
      for ( i = 0; i < 25; i++ )
         list[i] = (char)('z' - i);
      /* Write 25 characters to stream */
      numwritten = fwrite( list, sizeof( char ), 25, stream );
      printf( "Wrote %d items\n", numwritten );
      fclose( stream );

   }
   else
      printf( "Problem opening the file\n" );

   if( (stream = fopen( "fread.out", "r+t" )) != NULL )
   {
      /* Attempt to read in 25 characters */
      numread = fread( list, sizeof( char ), 25, stream );
      printf( "Number of items read = %d\n", numread );
      printf( "Contents of buffer = %.25s\n", list );
      fclose( stream );
   }
   else
      printf( "File could not be opened\n" );
}

看看这个文件的读写，把读取到的数据写入到二维数组中就可以了！！

[lixiaowei1234]

谢谢大虾！！！我总是对数据从文件中读取不大感冒。
有4列浮点型的200行数据，中间每一列之后有不定的空格，怎么处理空格和换行哪？？？
谢谢！！！

[lixiaowei1234]

望哪位好心人帮帮忙0.。。。