求一条拆分SQL语句

[王思明]

如何把下面的语句变成：
2012-09-05 2012-09-05 JD001 A中第六條 2012-09-05 JD000 B中第三條
2012-09-05 2012-09-05 JD001 A中第六條 2012-09-05 JD002 B中第六條

2012-09-05 2012-09-05 	JD001	A中第六條	'','',''
 '','',''                                       2012-09-05 	JD000	B中第三條
 '','',''                                	2012-09-05 	JD002	B中第六條

日期空格为1900-01-01 00:00:00也可以

[王思明]

我恨自己，不按时休息！

[王思明]

为什么？

[Felixzhaowenzhong]

DECLARE @TAB TABLE ([col1] varchar(1),[col2] int,[col3] int)
insert @TAB
select 'a',1,2 union all
select 'a',2,3 union all
select 'a',3,4 union all
select 'b',4,5 union all
select 'b',5,6 union all
select 'b',6,7
--------------开始查询--------------------------
select
   case px when 1 then col1 else '' end as col1,
   col2,col3
from
   (select px=row_number()over(partition by col1 order by getdate()),* from @TAB)t
/*
col1	col2	col3
a	1	2
	2	3
	3	4
b	4	5
	5	6
	6	7
	*/

[唐诗三百首]

第一行是7字段,第二三行是6字段,怎么匹配啊.

[汤姆克鲁斯]

SELECT  * FROM  TESTA  a  left join  TESTB  b on a.recdate= b.recdate
AND NOT EXISTS(SELECT 1 FROM TESTB WHERE recdate=b.recdate AND rmk<>b.rmk)
UNION ALL 
SELECT  a.recdate,'','',b.* FROM  TESTA  a   join  TESTB  b on a.recdate= b.recdate
AND  EXISTS(SELECT 1 FROM TESTB WHERE recdate=b.recdate AND rmk<>b.rmk)
ORDER BY a.recdate
/*

recdate	partno	rmk	recdate	partno	rmk
2012-09-01 00:00:00	JD000	A中第一條	2012-09-01 00:00:00	JD000	B中第一條
2012-09-02 00:00:00	JD000	A中第二條	2012-09-02 00:00:00	JD000	B中第二條
2012-09-04 00:00:00	JD000	A中第三條	NULL	NULL	NULL
2012-09-05 00:00:00	JD001	A中第六條	NULL	NULL	NULL
2012-09-05 00:00:00			2012-09-05 00:00:00	JD000	B中第三條
2012-09-05 00:00:00			2012-09-05 00:00:00	JD002	B中第六條
2012-09-06 00:00:00	JD000	A中第四條	2012-09-06 00:00:00	JD001	B中第五條
2012-09-11 00:00:00	JD001	A中第五條	NULL	NULL	NULL
*/