字符串变数组

[zhenghq1001]

string str = "01020304050607";

List<string> grp = new List<string>();

for (int i = 0; i <= 12; i += 2)
{
grp.add(str.substring(n,2));
}


把字符串"01020304050607"，变成了{"01","02","03","04","05","06","07"}


还有更简单的方法，或者说 效率更高的办法吗? 谢谢

[kensouterry1]

其实这个方法很通俗易懂的……

[threenewbee]

string str = "01020304050607";
List<string> grp = Regex.Matches(str, "\\d{2}").Cast<Match>().Select(x => x.Value).ToList();

手写的，不一定对。

[EnForGrass]

试试
string[] strs = "01020304050607".Split("(?<=\\G.{2})(?!$)");