求一个sql的问题急求!!

junjun19885871 2012-10-15 04:08:38
输入
date code change
2011.04.11 000000703-005523-029 s
2011.06.18 000000703-005523-029 d
2010.06.03 000000703-005736-007 s
2010.08.14 000000703-008227-020 s
2010.04.30 000000703-008227-021 s
2010.05.14 000000703-008240-004 s
2010.11.20 000000703-008278-013 s
2010.11.20 000000703-008278-022 s
2010.04.30 000000703-008282-014 s
2010.08.18 000000703-008299-016 s
2010.08.18 000000703-008299-019 s
2011.06.28 000000703-008899-000 s
2011.03.10 000000703-008899-004 s
2011.04.09 000000703-008899-004 d
2011.04.11 000000703-008899-004 u
2010.06.17 000000703-008899-005 s
2010.11.16 000000703-008899-005 d

输出

date code change
2011.04.11 000000703-005523-029 sd
2010.06.03 000000703-005736-007 s
2010.08.14 000000703-008227-020 s
2010.04.30 000000703-008227-021 s
2010.05.14 000000703-008240-004 s
2010.11.20 000000703-008278-013 s
2010.11.20 000000703-008278-022 s
2010.04.30 000000703-008282-014 s
2010.08.18 000000703-008299-016 s
2010.08.18 000000703-008299-019 s
2011.06.28 000000703-008899-000 s
2011.03.10 000000703-008899-004 sdu
2010.06.17 000000703-008899-005 sd

...全文
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E次奥 2012-10-15
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如果数据是现成的在某个文件里保存的话,写个程序循环插入。
junjun19885871 2012-10-15
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如果是插入到csv形式呢? 数据上万呢 楼上的 先谢谢了啊


汤姆克鲁斯 2012-10-15
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--> 测试数据:[tb]
IF OBJECT_ID('[tb]') IS NOT NULL DROP TABLE [tb]
GO
CREATE TABLE [tb]([date] DATETIME,[code] VARCHAR(20),[change] VARCHAR(1))
INSERT [tb]
SELECT '2011.04.11','000000703-005523-029','s' UNION ALL
SELECT '2011.06.18','000000703-005523-029','d' UNION ALL
SELECT '2010.06.03','000000703-005736-007','s' UNION ALL
SELECT '2010.08.14','000000703-008227-020','s' UNION ALL
SELECT '2010.04.30','000000703-008227-021','s' UNION ALL
SELECT '2010.05.14','000000703-008240-004','s' UNION ALL
SELECT '2010.11.20','000000703-008278-013','s' UNION ALL
SELECT '2010.11.20','000000703-008278-022','s' UNION ALL
SELECT '2010.04.30','000000703-008282-014','s' UNION ALL
SELECT '2010.08.18','000000703-008299-016','s' UNION ALL
SELECT '2010.08.18','000000703-008299-019','s' UNION ALL
SELECT '2011.06.28','000000703-008899-000','s' UNION ALL
SELECT '2011.03.10','000000703-008899-004','s' UNION ALL
SELECT '2011.04.09','000000703-008899-004','d' UNION ALL
SELECT '2011.04.11','000000703-008899-004','u' UNION ALL
SELECT '2010.06.17','000000703-008899-005','s' UNION ALL
SELECT '2010.11.16','000000703-008899-005','d'
--------------开始查询--------------------------

SELECT [date]=MIN([date]),[code],[change]=(SELECT ''+[change] FROM [tb] WHERE [code]=t.[code] FOR XML PATH('')) FROM [tb] AS t
GROUP BY [code]
----------------结果----------------------------
/*
date code change
2011-04-11 00:00:00.000 000000703-005523-029 sd
2010-06-03 00:00:00.000 000000703-005736-007 s
2010-08-14 00:00:00.000 000000703-008227-020 s
2010-04-30 00:00:00.000 000000703-008227-021 s
2010-05-14 00:00:00.000 000000703-008240-004 s
2010-11-20 00:00:00.000 000000703-008278-013 s
2010-11-20 00:00:00.000 000000703-008278-022 s
2010-04-30 00:00:00.000 000000703-008282-014 s
2010-08-18 00:00:00.000 000000703-008299-016 s
2010-08-18 00:00:00.000 000000703-008299-019 s
2011-06-28 00:00:00.000 000000703-008899-000 s
2011-03-10 00:00:00.000 000000703-008899-004 sdu
2010-06-17 00:00:00.000 000000703-008899-005 sd
*/

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