sql做连续减法怎么办？

[qian2988]

(isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='04' and cq_ctime<=:etime),0) -
isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='03' and cq_ctime<=:etime),0) ) as totaldinner

//通过
(isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='04' and cq_ctime<=:etime),0) -
isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='05' and cq_ctime<=:etime),0) -
isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='03' and cq_ctime<=:etime),0) ) as totaldinner-
//通不过

[shoppo0505]

你的第二段Code， as totaldinner 后多了一个 减号， 去掉再试试。

[qian2988]

这个是我复制多了.....原句里没有的。。

[Viccy_Yao]

select (isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='04' and cq_ctime<=:etime),0)-
isnull((select sum(cq_dinner) from cjf_card_dzcq where cq_cardno=a.c_incode and cq_type='03' and cq_ctime<=:etime),0) ) as totaldinner

在前面加个select试试