急！求一PHP正则表达式提取字符串，在线等！

[levinstong]

HTTP/1.1 200 OK Server: Apache-Coyote/1.1 Date: Wed, 17 Oct 2012 07:05:19 GMT Content-Type: application/json Content-Length: 169 Connection: close {"UserDTO":{"comIndustry":2,"comType":2,"email":"[e-mail]","industry":3,"telephone":13333333333,"userId":111944,"userType":1,"username":"请输入公司名称"}}


有上面这一串字符，{"UserDTO":{"comIndustry":2,"comType":2,"email":"[e-mail]","industry":3,"telephone":13333333333,"userId":111944,"userType":1,"username":"请输入公司名称"}}这一段是我要正则提取出来的 谢谢！！

[一起混吧]

preg_match('/\{(.*)\}/s',$s,$m);
echo $m[1];

[xuzuning]

费那劲干什么？抓取时不要http头不就行了？

[levinstong]

[Quote=引用 2 楼 的回复:]

费那劲干什么？抓取时不要http头不就行了？
[/Quote]
怎么不要头呢 ？代码如下

$Cookie=$config_login["cookie_name"]."=".$cookie_value.";";
		try{
			$fp = fsockopen($config_login["host"], $config_login["prot"], $errno, $errmsg);
			fwrite($fp, "GET ".$config_login["sitepate"].$config_login["url"]." HTTP/1.1\r\n");
			fwrite($fp, "Accept: application/".$config_login["accept"]."\r\n");
			fwrite($fp, "Cookie: ".$Cookie.";\r\n");
			fwrite($fp, "Host: ".$config_login["host"]."\r\n");
			fwrite($fp, "User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; zh-CN; rv:1.9.2.16) Gecko/20110319 Firefox/3.6.16 GTB7.1\r\n");
			fwrite($fp, "Connection: Close\r\n\r\n");
		} catch (Exception $e) {
			die('fsock error');
			exit;
		}

		$xmlstr = '';
		while (!feof($fp)) {
			$xmlstr .= fgets($fp, 128);
		}
    	fclose($fp);

[xuzuning]

$h = 0;
while (!feof($fp)) {
$t = fgets($fp, 128);
if(!$h && $t == "Connection: close\r\n") {
$xmlstr = '';
$h++;
}
$xmlstr .= $t;
}