一个正则

[wklken]

字符串：
"1=a,2=b,3=,,e,4=^A,5=,"

re.findall(r"这里", "1=a,2=b,3=,,e,4=^A,5=,")

目的是，逗号分隔，取k=value的值，直到最后一个逗号

要求返回：
1=a
2=b
3=,,e
4=^A
5=,

试了很多，均达不到要求
求助啊

thx!

[zjs100901]

str = "1=a,2=b,3=,,e,4=^A,5=,"
L = re.findall( "\d+=\D*", str )
print L

输出： ['1=a,', '2=b,', '3=,,e,', '4=^A,', '5=,'] 这样行不？

[angel_su]

分割嘛试试re.split... >>> import re >>> re.split(r'(?<=\w),(?=\d)', "1=a,2=b,3=,,e,4=^A,5=,") ['1=a', '2=b', '3=,,e', '4=^A', '5=,'] >>>

[千树之影]

import re
str = "1=a,2=b,3=,,e,4=^A,5=,"
L = re.findall( r"\d.*?(?=,\d)|\d.*,$",str )
print L

结果： ['1=a', '2=b', '3=,,e', '4=^A', '5=,']

[bugs2k]

Python 2.7.3 (default, Apr 10 2012, 23:31:26) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> import re
>>> text = "1=a,2=b,3=,,e,4=^A,5=,"
>>> mat = re.findall('(\w+=.*?),', text)
>>> print mat
['1=a', '2=b', '3=', '4=^A', '5=']
>>>