在SQL Server中,如何用语句实现：查询某字段的本行记录值如果等于上一行记录值，则本行值+1？

[chiclyer]

表Table中有如下2列数据：
ID 记录值
-------------------------
1 3000
2 3200
3 3500
4 3500
5 3700
6 3900
7 3900
8 3900
9 4100

返回结果：

ID 记录值
-------------------------
1 3000
2 3200
3 3500
4 3501
5 3700
6 3901
7 3902
8 3903
9 4100

[newtee]

帮顶下

[longai123]

update tb 记录值=记录值+1 where id=(select id from tb as a where a.id=id-1 and a.记录值=记录值)

[kensouterry1]

;WITH c1(ID, 记录值)
AS
(
SELECT 1, 3000 UNION ALL
SELECT 2, 3200 UNION ALL
SELECT 3, 3500 UNION ALL
SELECT 4, 3500 UNION ALL
SELECT 5, 3700 UNION ALL
SELECT 6, 3900 UNION ALL
SELECT 7, 3900 UNION ALL
SELECT 8, 3900 UNION ALL
SELECT 9, 4100
)
----start query
,c2 AS
(
SELECT
	b.ID,
	CASE WHEN a.记录值 = b.记录值 THEN b.记录值+1 ELSE b.记录值 END 记录值
FROM c1 a
LEFT JOIN c1 b ON a.ID = b.ID - 1 --(b大)
UNION ALL
SELECT TOP 1
	ID,
	记录值
FROM c1
)
SELECT *
FROM c2
ORDER BY ID

--测试结果：
ID          记录值
----------- -----------
NULL        NULL
1           3000
2           3200
3           3500
4           3501
5           3700
6           3900
7           3901
8           3901
9           4100

(10 row(s) affected)

[坚_持]

declare @ta table(ID int,记录值 int)
insert @ta select 1,3000 union all select 2,3200 union all select 3,3500 union all select 4,3500 union all
select 5,3700 union all select 6,3900 union all select 7,3900 union all select 8,3900 union all
select 9,3900 union all select 10,3900 union all select 11,3900 union all select 12,4100
DECLARE @N INT,@I1 INT
SET @N = 1
set @I1 = 1
WHILE @N<(SELECT MAX(ID) FROM @ta)
BEGIN
while @N+1<(SELECT MAX(ID) FROM @ta)
begin
IF (SELECT 记录值 FROM @ta where ID = @N)=(SELECT 记录值 FROM @ta where ID = @N+1)
begin
update @ta set 记录值=记录值+@I1 from @ta where ID = @N+1
end
set @N = @N+1
IF (SELECT 记录值-@I1 FROM @ta where ID = @N)=(SELECT 记录值 FROM @ta where ID = @N+1)
begin
set @I1 = @I1+1
update @ta set 记录值=记录值+@I1 from @ta where ID = @N +1
end
end
set @I1 = 1 set @N = @N+1
END
select * from @ta

[唐诗三百首]

原5,6行,3700不等于3900,为何结果是 ID 记录值 ---------- 5 3700 6 3901

[javatemptation]

猜测楼主的数据如下： 1 3000 2 3200 3 3500 4 3500 5 3900 6 3900 7 3900 8 3900 9 4100

USE tempdb;
/*
CREATE TABLE t1
(
	id INT NOT NULL,
	result int NOT NULL
);
INSERT INTO t1(id,result) VALUES
(1,3000),(2,3200),(3,3500),(4,3500),(5,3900),(6,3900),(7,3900),(8,3900),(9,4100);
*/
SELECT * FROM t1;

SELECT 
	t2.id,(t2.result + t2.number) AS result
FROM
(
	SELECT 
	*,ROW_NUMBER() OVER(PARTITION BY t1.result ORDER BY t1.id) - 1 AS number
	FROM t1
) AS t2

生成的效果如下： 1 3000 2 3200 3 3500 4 3501 5 3900 6 3901 7 3902 8 3903 9 4100

[發糞塗牆]

按照你的说法，第三行应该是3501，第四行是3502

/*
 CREATE TABLE test (id INT ,记录值 varchar(10) )
 INSERT INTO dbo.test
 SELECT 1, 3000 UNION ALL
 SELECT 2, 3200 UNION ALL
 SELECT 3, 3500 UNION ALL
 SELECT 4, 3500 UNION ALL
 SELECT 5, 3700 UNION ALL
 SELECT 6, 3900 UNION ALL
 SELECT 7, 3900 UNION ALL
 SELECT 8, 3900 UNION ALL
 SELECT 9, 4100
 */
 
 --不相等的值
 SELECT * FROM test a WHERE EXISTS(SELECT 1 FROM (SELECT 记录值 FROM test GROUP BY 记录值 HAVING COUNT(1)<2) b WHERE a.记录值=b.记录值)
 UNION ALL 
 --有相同的值
 SELECT id,LEFT(记录值,3)+CONVERT(VARCHAR(10),ROW_NUMBER()OVER (PARTITION BY 记录值 ORDER BY id) )
 FROM test a WHERE EXISTS(SELECT 1 FROM (SELECT 记录值 FROM test GROUP BY 记录值 HAVING COUNT(1)>1) b WHERE a.记录值=b.记录值)
 ORDER BY id
 
 /*
 id          记录值
 ----------- ----------------
 1           3000
 2           3200
 3           3501
 4           3502
 5           3700
 6           3901
 7           3902
 8           3903
 9           4100
 
 (9 行受影响)
 
 */