画正方体``````?

Q3277631 2012-11-27 02:47:08

{

	int flag,r,h;

	double pi,x,y,z,cx,cy,thx,thy,th;

	double xw,yw,zw;

	

	pi=3.14159;

	cx=320;//起始位置

	cy=180;

	int ed=2000,eh=100,od=400,hl=1; 



	h=80; thy=0.2;r=100;n=4;thx=0.2;

	flag=0;nn=1;

	

	for(th=0;th<=2*pi+0.1;th+=2*pi/n)

	{

		x=r*cos(th); y=h; z=r*sin(th);

		

		//Call rot_y: Call rot_x

		zw=z; xw=x;

		x=zw*cos(thy)-xw*sin(thy);

		z=zw*sin(thy)+xw*cos(thy);

		

		yw=y; zw=z;

		y=yw*cos(thx)-zw*sin(thx);

		z=yw*sin(thx)+zw*cos(thx);

		

		if(ps==1){

			x=x*ed/(ed-od-z);

			y=(y*ed-eh*(od+z))/(ed-od-z);

		}

		//ax[nn]=x; ay[nn]=y; az[nn]=z;

		XP[nn]=x; YP[nn]=y; ZP[nn]=z;

		nn=nn+1;

	}

	

	flag=0;nn=1;



	for(th=0;th<=2*pi+0.1;th+=2*pi/n){

		x=r*cos(th); y=-h; z=r*sin(th);

		

		//Call rot_y: Call rot_x

		zw=z; xw=x;

		x=zw*cos(thy)-xw*sin(thy);

		z=zw*sin(thy)+xw*cos(thy);

		

		yw=y; zw=z;

		y=yw*cos(thx)-zw*sin(thx);

		z=yw*sin(thx)+zw*cos(thx);

		

		if(ps==1){

			x=x*ed/(ed-od-z);

			y=(y*ed-eh*(od+z))/(ed-od-z);}

		//bx[nn]=x; by[nn]=y; bz[nn]=z;

		XP[nn+4]=x; YP[nn+4]=y; ZP[nn+4]=z;

		nn=nn+1;

	}

	

	CP[1] = 1;CP[2] = 1;CP[3] = 1; CP[4] = 1;CP[5] = 1;CP[6] = 1;CP[7] = 1;CP[8] = 1;	

	

}

实在是看不懂for循环中的操作,
zw=z; xw=x;
x=zw*cos(thy)-xw*sin(thy);
z=zw*sin(thy)+xw*cos(thy);
yw=y; zw=z;
y=yw*cos(thx)-zw*sin(thx);
z=yw*sin(thx)+zw*cos(thx);

if(ps==1){
x=x*ed/(ed-od-z);
y=(y*ed-eh*(od+z))/(ed-od-z);

这几句到底什么意思?

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