为什么html中form的method是get，为什么我最后提交数据时地址栏没有显示数据，不是post没有吗？

2012-12-15 12:22:36 724 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

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html文件代码如下





<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">



<html >

<head></head>

<body>

<form id = "form1" name = "form1" method = "post" action ="servlet/ThreeParams">

	<table width = "234" border = "2">

		<tr>

			<td width = "90">param1</td>

			<td width = "90"><input name = "param1" type = "text" id="param1" /> </td>

		</tr>

		<tr>

			<td width = "90">param2</td>

			<td width = "90"><input name = "param2" type = "text" id="param2" /> </td>

		</tr>

		<tr>

			<td width = "90">param3</td>

			<td width = "90"><input name = "param3" type = "text" id="param3" /> </td>

		</tr>

		<tr>

			<td> </td>

			<td><label>

				<input type="submit" value="提交">

				</label></td>

		</tr>

	</table>

</form>

</body>

</html>

servlet的java源代码如下

import java.io.IOException;

import java.io.PrintWriter;



import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;





public class ThreeParams extends HttpServlet {



	@Override

	protected void doGet(HttpServletRequest req, HttpServletResponse resp)

			throws ServletException, IOException {

		PrintWriter pw = resp.getWriter();

		resp.setContentType("text/html");

		pw.println(req.getParameter("param1"));

		pw.println("<br/>");

		pw.println(req.getParameter("param2"));

		pw.println("<br/>");

		pw.println(req.getParameter("param3"));

		pw.println("<br/>");

	}



	protected void doPost(HttpServletRequest req, HttpServletResponse resp)

			throws ServletException, IOException {

			doGet(req,resp);

	}



}