这段json怎么解析

lovezx1028 2013-01-13 01:09:32

L.detal={
"info": {"name":"lzhr","noMark":false,"age":"28"} ,
"address":{"ssadd":"广东","city":"yc"},
"school":[{"city":"yc","address":"河㙟"},{"city":"yc","address":"阳春"},{"city":"荆州","address":"荆州市"}]
}
怎么解析！谢谢

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高三石 2013-02-19

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引用 2 楼 z284122755 的回复:

PHP code?123456789 $a='{ "info": {"name":"lzhr","noMark":false,"age":"28"} , "address":{"ssadd":"??","city":"yc"}, "school":[{"city":"yc","address":"??"},{"city":"yc","address":"??"},……

liuser_cn 2013-02-06

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结贴吧少年！

phpteam001 2013-02-06

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经测试，PHP范围PHP 5 >= 5.2.0 用json_decode()函数可以解析的哈。

jxdyzwh 2013-01-14

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用json_decode，其实楼主也可以用Charles这个工具来分析下你的JOSN是否正确，我最近经常使用这个软件，觉得很方便，特别是对于JSON数据交互这块

只要开心就好 2013-01-14

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json_decode 不过他的使用要看你的PHP版本，适用范围是PHP 5 >= 5.2.0 如果PHP版本比较低，可以去网上下一个php的JSON解析类

www_7di_net 2013-01-14

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引用 2 楼 z284122755 的回复:

PHP code?123456789 $a='{ "info": {"name":"lzhr","noMark":false,"age":"28"} , "address":{"ssadd":"??","city":"yc"}, "school":[{"city":"yc","address":"??"},{"city":"yc","address":"??"},……

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魔术世界中文版 2013-01-13

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	$a='{
 "info": {"name":"lzhr","noMark":false,"age":"28"} ,
 "address":{"ssadd":"??","city":"yc"},
  "school":[{"city":"yc","address":"??"},{"city":"yc","address":"??"},{"city":"??","address":"???"}]
 }';
	echo "<pre>";
	print_r(json_decode($a,true));//解析成数组
          print_r(json_decode($a));//解析成对象
	echo "</pre>";