Postmessage多窗口同时后台点击鼠标问题

[www7788softcom]

对多游戏窗口同时操作时 经常会发生简单的单击操作被处理成 单击按下后拖动子窗口到当前鼠标位置的效果请教下如何处理？
/// <summary>
/// 后台发送鼠标POST
/// </summary>
/// <param name="hWnd"></param>
/// <param name="x"></param>
/// <param name="y"></param>
public static void LeftClickBackP(int hWnd, int x, int y)
{

const uint downCode = 0x201; // Left click down code
const uint upCode = 0x202; // Left click up code

//PostMessage((IntPtr)hWnd, downCode | upCode, 1, MakeLParam(x, y)); // Mouse button down


PostMessage((IntPtr)hWnd, downCode, 1, MakeLParam(x, y)); // Mouse button down
//Thread78.Sleep(100);
PostMessage((IntPtr)hWnd, upCode, 1, MakeLParam(x, y)); // Mouse button up
//Thread78.Sleep(100);
}

[www7788softcom]

uuppuupp

[失落的神庙]

 /// <summary>
        /// 后台发送鼠标POST
        /// </summary>
        /// <param name="hWnd"></param>
        /// <param name="x"></param>
        /// <param name="y"></param>
        public static void LeftClickBackP(int hWnd, int x, int y)
        {

            const uint downCode = 0x201; // Left click down code 
            const uint upCode = 0x202; // Left click up code 

            PostMessage((IntPtr)hWnd, downCode | upCode, 1, MakeLParam(x, y)); // Mouse button down 

           //Thread.Sleep(100);
            PostMessage((IntPtr)hWnd, downCode, 1, MakeLParam(x, y)); // Mouse button down 
            Thread.Sleep(100);
            PostMessage((IntPtr)hWnd, upCode, 1, MakeLParam(x, y)); // Mouse button up 
            Thread.Sleep(100);
        } 

因为拖拽的窗体需要先被激活 然后才能执行点击操作 所以第一个鼠标按下是执行了窗体激活 第二个才是按下 第三个是松开

[www7788softcom]

不是这样的吧？后台点击的也要激活窗体？

[bdmh]

不太清楚你的多窗口操作是怎么个发送的信息，你改用Sendmessage试试呢，postmessage是异步的，不知道会不会由于多窗口而受到影响