1楼正解，已验证
DROP TABLE IF EXISTS T1;
CREATE TABLE T1(2id INT,groupId INT,tagLibId INT,bySort INT,buyerId INT,ownerId INT,tagId INT);
INSERT INTO T1 VALUES
(2001,1,1,0,1,16,2001),
(2007,2,11,0,2,16,2007),
(2008,2,12,0,3,16,2008),
(2014,3,22,0,4,16,2014),
(2013,3,21,0,6,16,2013),
(2002,1,2,0,14,16,2002),
(2003,1,3,0,15,16,2003),
(2018,4,51,0,16,16,2018),
(2004,1,4,0,17,16,2004),
(2009,2,13,0,18,16,2009),
(2001,1,1,0,25,1001,2001),
(2007,2,11,0,26,1001,2007),
(2002,1,2,0,30,1002,2002),
(2019,4,52,0,31,1002,2019),
(2008,2,12,0,35,1002,2008),
(2054,13,2,0,1001,1501,2054),
(2029,11,51,0,1002,1501,2029),
(2045,12,71,0,1003,1501,2045),
(2046,12,72,0,1004,1501,2046),
(2030,11,52,0,1005,1501,2030),
(2059,21,82,0,1007,2001,2059),
(2060,21,83,0,1008,2001,2060),
(2065,31,94,0,1009,2002,2065),
(2062,31,91,0,1010,2002,2062),
(2063,31,92,0,1011,2002,2063),
(2018,4,51,0,1501,1001,2018),
(2022,5,41,0,1502,1001,2022),
(2013,3,21,0,1503,1001,2013),
(2025,5,44,0,1504,1002,2025),
(2014,3,22,0,1505,1002,2014);
SELECT ownerId FROM T1 WHERE tagid IN (2001,2007) GROUP BY ownerId HAVING COUNT(DISTINCT tagid)=2
