非常简单的小问题

[LI-O]

#include<stdio.h>
int main(void)
{
float weight;
float value;
printf("Are you worth your weight in rhodium?\n");
printf("Let's check it out\n");
printf("please enter your weight in pounds:");
scanf("%f",&weight);
value=770*weight*14.5833;
printf("Your weight in rhodium is worth $%.2f.\n",value);
printf("You are easily worth that!if rhodium prices drop.\n");
printf("est more to maintain your value.\n");
return 0;
}
在这个东西里面的
printf("Your weight in rhodium is worth $%.2f.\n",value);
。。其中 $%.2f 求详解。。

[lee_鹿游原]

在C语言中用%m.n加数据类型，表示以某种数据类型且宽度为M小数点后保留N位小数输出。

[LI-O]

那这个的意思就是 以某种数据类型且宽度为 0 小数点后保留2位小数输出？？ 还有 什么是宽度？？？

[lee_鹿游原]

为什么不动手试呢？

[LI-O]

试过了。。。尝试修改过 问题是在修改%m.n中的M时 看不到程序结果的变化。。所以。。，，，，，

[prajna]

printf("%w.pf.\n", f); w -- width （寬度） p -- precision (精度) 試一下下面的例子就明白了。 printf("Your weight in rhodium is worth $%.2f.\n",value); printf("Your weight in rhodium is worth $%7.2f.\n",value); printf("Your weight in rhodium is worth $%.5f.\n",value); printf("Your weight in rhodium is worth $%7.5f.\n",value); printf("Your weight in rhodium is worth $%3.5f.\n",value);

[LI-O]

用了这个代码试的

[LI-O]

#include<stdio.h> int main(void) { float a; printf("输入:\n"); scanf("%f",&a); printf("Your weight in rhodium is worth $%.2f.\n",a); printf("Your weight in rhodium is worth $%7.2f.\n",a); printf("Your weight in rhodium is worth $%.5f.\n",a); printf("Your weight in rhodium is worth $%7.5f.\n",a); printf("Your weight in rhodium is worth $%3.5f.\n",a); } 然后 输入5 结果 宽度还是 没有什么区别的。。囧