怎么读出sql中某个数据库的当前容量大小

[woshidaniubi123]

因为我要做个数据库监视功能 要读出当前选择的数据库的大小 百度无果来此提问

[woshidaniubi123]

引用 2 楼 foren_whb 的回复:

SQL code?123SELECT DB_NAME(database_id) AS [Database Name],[Name] AS [Logical Name],[Physical_Name] AS [Physical Name],((size * 8) / 1024) AS [Size(MB)],[differential_base_time] AS [Diffe……

能给个实例吗 这种写法我看不太懂。。

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[showlin]

给你翻译一下好了

SELECT DB_NAME(database_id) 
AS [数据库名],[Name] AS [逻辑名],[Physical_Name] AS [物理文件],
((size * 8) / 1024) AS [大小(MB)],[differential_base_time] AS [差异北方时间] 
 FROM sys.master_files  WHERE DB_NAME(database_id) IN('这里是你的数据库名')

复制，在sql server management studio里头查询执行

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[woshidaniubi123]

引用 6 楼 showlin 的回复:

给你翻译一下好了 SQL code?1234SELECT DB_NAME(database_id) AS [数据库名],[Name] AS [逻辑名],[Physical_Name] AS [物理文件],((size * 8) / 1024) AS [大小(MB)],[differential_base_time] AS [差异北方时间] FROM sys.maste……

我以为要把中括号里面的都给改成我需要的东西呢 原来这个只是复制就行了。

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[jhdxhj]

复制，在sql server management studio里头查询执行

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[insus]

Refer: http://www.cnblogs.com/insus/archive/2012/12/21/2827531.html http://www.cnblogs.com/insus/archive/2012/07/31/2610372.html

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[bdmh]

参考http://dev.yesky.com/481/8352981.shtml

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[丰云]

SELECT DB_NAME(database_id) AS [Database Name],[Name] AS [Logical Name],[Physical_Name] AS [Physical Name],((size * 8) / 1024) AS [Size(MB)],[differential_base_time] AS [Differential Base Time] 
FROM sys.master_files 
WHERE DB_NAME(database_id) IN('XXX')

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[yyl8781697]

这种很多啊 直接用sql语句就可以 LS的应该就能满足LZ了

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[夜色镇歌]

引用 2 楼 foren_whb 的回复:

SQL code?123SELECT DB_NAME(database_id) AS [Database Name],[Name] AS [Logical Name],[Physical_Name] AS [Physical Name],((size * 8) / 1024) AS [Size(MB)],[differential_base_time] AS [Diffe……

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