>>> A = [[[3, 5], [0, 2], [2, 10]], [[6, 9], [7, 2], [9, 7]], [[3, 3], [5, 3], [10, 2]]] >>> B = [[0, 2], [2, 10], [3, 3]] >>> C = [[B.count(x) for x in y] for y in A] >>> C [[0, 1, 1], [0, 0, 0], [1, 0, 0]]
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