python列表的一个问题

[ws0308]

有两个列表A,B

A = [[[3, 5], [0, 2], [2, 10]], [[6, 9], [7, 2], [9, 7]], [[3, 3], [5, 3], [10, 2]]];

B = [[0, 2], [2, 10], [3, 3]];

B中的每个元素都在A中，出现过记做1，否则为0

怎么得到[[0, 1, 1], [0, 0, 0], [1, 0, 0]]？

[libralibra]

你又发这儿来了,[0,1,1]是怎么来的啊?

[libralibra]

好了,还是去那边看到了描述,你写反了,是检测A中元素在B中的次数

>>> A = [[[3, 5], [0, 2], [2, 10]], [[6, 9], [7, 2], [9, 7]], [[3, 3], [5, 3], [10, 2]]]
>>> B = [[0, 2], [2, 10], [3, 3]]
>>> C = [[B.count(x) for x in y] for y in A]
>>> C
[[0, 1, 1], [0, 0, 0], [1, 0, 0]]