怎么使用jQuery解析这段json类型的数据

ChinaXtHuLang 2013-02-19 05:52:39

[{"objName":"datalist","objUser":[{"sUserName":"JSON0","sAddress":"中国-北京-海淀0号"},{"sUserName":"JSON1","sAddress":"中国-北京-海淀1号"},{"sUserName":"JSON2","sAddress":"中国-北京-海淀2号"},{"sUserName":"JSON3","sAddress":"中国-北京-海淀3号"},{"sUserName":"JSON4","sAddress":"中国-北京-海淀4号"}]}]

这是我写的。搞不定啊.

$(function() {

	var json = [{"objName":"datalist","objUser":[{"sUserName":"JSON0","sAddress":"中国-北京-海淀0号"},{"sUserName":"JSON1","sAddress":"中国-北京-海淀1号"},{"sUserName":"JSON2","sAddress":"中国-北京-海淀2号"},{"sUserName":"JSON3","sAddress":"中国-北京-海淀3号"},{"sUserName":"JSON4","sAddress":"中国-北京-海淀4号"}]}]

    var data = eval('(' + json + ')');

    alert(data.objName);

    $.each(data.objUser,

    function(i, o) {

        alert(o.sAddress);

    });

})

我要弹出提示：datalist,然后是每个sAddress的值

求高人指点

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ILOVE_ASPNET 2013-02-20

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楼主你这里不需要eval转换，就楼上说的，你当前json也是object类型了，不需要转换的，你可以 console.info(typeof json) 一下就知道了 ,如果是string,你才需要eval的，不过这里个人有点建议不要用eval ,改用new Function的方式 var b = new Function("return " + json); return b.apply(this); 感觉这个兼容性，性能会好点。

魔术世界中文版 2013-02-19

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<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">	
	$(function() {
		var json = [{"objName":"datalist","objUser":[{"sUserName":"JSON0","sAddress":"中国-北京-海淀0号"},{"sUserName":"JSON1","sAddress":"中国-北京-海淀1号"},{"sUserName":"JSON2","sAddress":"中国-北京-海淀2号"},{"sUserName":"JSON3","sAddress":"中国-北京-海淀3号"},{"sUserName":"JSON4","sAddress":"中国-北京-海淀4号"}]}];
		var a=json[0].objUser;
		var cnt=json[0].objUser.length;
		alert(json[0].objName);
		for(var i=0;i<cnt;i++){
			alert(a[i].sAddress);
		}
	})
</script>

「已注销」 2013-02-19

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json变量本来就是JSON格式的了，LZ为什么还要用var data = eval('(' + json + ')');把这红色这句去了。


$(function() {
    var json = [
                  {
                      "objName":"datalist",
                      "objUser":[
                                  {"sUserName":"JSON0","sAddress":"中国-北京-海淀0号"},
                                  {"sUserName":"JSON1","sAddress":"中国-北京-海淀1号"},
                                  {"sUserName":"JSON2","sAddress":"中国-北京-海淀2号"},
                                  {"sUserName":"JSON3","sAddress":"中国-北京-海淀3号"},
                                  {"sUserName":"JSON4","sAddress":"中国-北京-海淀4号"}
                                ]
                  }
                ];  
    $.each(json[0].objUser,function(i, o) {
        alert(o.sAddress);
    });
})

job_xiao 2013-02-19

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var json = [{"objName":"datalist","objUser":[{"sUserName":"JSON0","sAddress":"中国-北京-海淀0号"},{"sUserName":"JSON1","sAddress":"中国-北京-海淀1号"},{"sUserName":"JSON2","sAddress":"中国-北京-海淀2号"},{"sUserName":"JSON3","sAddress":"中国-北京-海淀3号"},{"sUserName":"JSON4","sAddress":"中国-北京-海淀4号"}]}];
for(i in json){
     alert(json[i].objName);
     for(s in json[i].objUser){
        alert(json[i].objUser[s].sAddress);
       }
}