求救，初学servlet遇到的问题

ivent1314 2013-03-13 09:34:59

这是该JAVA文件的源代码
package hello;

import java.io.IOException;
import java.io.PrintWriter;
import java.util.Date;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class ClientServlet extends HttpServlet {

/**
* Constructor of the object.
*/
public ClientServlet() {
super();
}

/**
* The doGet method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to get.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/

/**
* The doPost method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to post.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {

response.setContentType("text/html");
PrintWriter out = response.getWriter();
out
.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println(" <BODY>");
out.print(" This is ");
out.print(this.getClass());
out.println(", using the POST method");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}
public void userInterface(HttpServletResponse response)throws IOException
{
PrintWriter out=response.getWriter();
out.println("<html>");
out.println("<head><title>loginservlet</title></head>");
out.println("<body bgcolor=\"#ffffff\">");
out.println("<h1 align=center>欢迎第一次使用Servlet</h1>");
out.println("<form method=post action=/ServletModule/loginservlet");
out.println("<br/>");
out.println("用户名：<input type='text' name='username'><br/>");
out.println("密码：<input type='password' name='password'><br/>");
out.println("<input type=submit value='提交'><br/>");
out.println("</form>");
out.println("</body>");
out.println("</html>");
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setCharacterEncoding("GB2312");

response.setContentType("text/html");
PrintWriter out = response.getWriter();
try {
String username = request.getParameter("username");
String password = request.getParameter("password");
if (username.equals("") || password.equals("")){
userInterface(response);
}
else{
out.println("<b>"+username + "</b> 欢迎第一次使用Servlet<br/>");
out.println("<b>今天的日期是：</b>" + new Date());
}
}
catch(Exception e){
userInterface(response);
}
out.close();
}

/**
* Initialization of the servlet. <br>
*
* @throws ServletException if an error occurs
*/
public void init() throws ServletException {
// Put your code here
}

}

尝试了很多次，每次输入用户名和密码时都出现HTTP Status 404的错误。求大神指导！

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kissoday 2013-03-14

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你的URL配置有问题吧。。把你的那个servlet的类放到一个包里，然后重新配置下web.xml中servlet的URL 把Tomcat的临时文件清理一下，重新加载下应该就能解决问题了。遇到问题应该了解问题本质。 404错误就是系统找不到文件路径。知道问题根本，解决问题也会变得容易的多。

ivent1314 2013-03-14

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引用 10 楼 yulongde77 的回复:

初学一定要仔细，一步一个脚印，要熟悉流程。 out.println("<h1 align=center>欢迎第一次使用Servlet</h1>"); out.println("<form method=post action=/ServletModule/loginservlet"); out.println("<br/>"); ……

好了，谢谢！

GreyZeng 2013-03-14

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web.xml可能没有配置对

花谢尊前不敢香 2013-03-14

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在web.xml里配置

<servlet>
    <servlet-name>ClientServlet</servlet-name>
    <servlet-class>hello.ClientServlet</servlet-class>
  </servlet>
 
 
   
  <servlet-mapping>
    <servlet-name>ClientServlet</servlet-name>
    <url-pattern>/ClientServlet</url-pattern>
  </servlet-mapping>

General-M 2013-03-14

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上web.xml

百八烦恼风 2013-03-14

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404那就是没找到咯，看看配置咯，

wangjiangbo2 2013-03-14

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404错误，web.xml设置servlet指向，你没有调用对。

ivent1314 2013-03-14

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是的 out.println("<form method=post action=/ServletModule/loginservlet");是这个错误了，没有该路径，应该如何该才能回到doget（）呢

海逸_2018 2013-03-14

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初学一定要仔细，一步一个脚印，要熟悉流程。
out.println("<h1 align=center>欢迎第一次使用Servlet</h1>");
out.println("<form method=post action=/ServletModule/loginservlet");
out.println("<br/>");

这里的action路径从哪里来的呢？

ivent1314 2013-03-14

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不显示哪个地方错误

ivent1314 2013-03-14

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<servlet> <servlet-name>ClientServlet</servlet-name> <servlet-class>hello.ClientServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ClientServlet</servlet-name> <url-pattern>/ClientServlet</url-pattern> </servlet-mapping> 已经改成这样了，但还是显示错误，而且myEclipse又不显示错误

IMBA__小八 2013-03-13