ruby 字符匹配验证问题

[hanluner]

业务中需要输入手机号码,现在我整理了11位手机号码的前三位的区段,现在不知道怎么写匹配验证

比如得到一个手机号 [phone],如何匹配前三位,求教代码.

[babyding]

"13400004444"=~/1{1}[2,3,4]{1}[0-9]{1}[0-9]{8}/ this expression will return index when match, else return nil first bit will match 1 and only match one times. the second bit will match 2 or 3 or 4, also only one times. the third bit will match any digit in 0-9, and only match one times. the other bits will match any digit e.g. 13400004444==>0 22400004444==>nil 16400004444==>nil 14400004444==>0 15400004444==>nil

[woodAstone2008]

我想说的是 非13 14 15 18 开头的手机号都是非正常的手机号吧 if "手机号".to_s.match(/^1[3|4|5|8]\d{9}$/).blank? return "正确" end

[woodAstone2008]

当然了 上面那个仅仅是对掐面开头的进行过滤了

[wccxiaoan]

/(\d\d\d)\d\d\d\d\d\d\d\d/.match("手机号") puts $1 => 前三位 >0<