有用Qt模拟post发送账户密码实现登陆的么？

zheguzai000 2013-04-14 04:29:06

这两天突然对这个感兴趣，找了个网站，首先用用浏览器打开网页输入账户密码，提交的时候用HttpAnalyze软件将post的信息抓下来

我登陆的网站是www.easyhits4u.com

获取到的post的信息如下：

POST /account.cgi HTTP/1.1

Accept: image/gif, image/jpeg, image/pjpeg, image/pjpeg, application/x-shockwave-flash, application/x-ms-application, application/x-ms-xbap, application/vnd.ms-xpsdocument, application/xaml+xml, */*

Referer: http://www.easyhits4u.com/

Accept-Language: zh-cn

User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 2.0.50727; .NET CLR 3.0.04506.648; .NET CLR 3.5.21022; .NET4.0C; .NET4.0E)

Content-Type: application/x-www-form-urlencoded

Accept-Encoding: gzip,deflate

Host: www.easyhits4u.com

Connection: Keep-Alive

Cache-Control: no-cache

Content-Length: 87



f=logon&manual=1&fb_id=&fb_token=&google_code=&username=joke&password=qazwsxedc&x=7&y=5

做了一个按钮，按钮中实现的内容如下：





    //这里是构造要发送的数据

    QByteArray postData;

    postData.append("f=logon&manual=1&fb_id=&fb_token=&username=");

    postData.append(ui->lineEdit_user->text());

    postData.append("&password=");

    postData.append(ui->lineEdit_Passwd->text());

    postData.append("&x=7&y=5");





    request = new QNetworkRequest(QUrl("http://www.easyhits4u.com/account.cgi"));



    //request->setUrl(param);

    //request->setHeader();

    request->setUrl(QUrl("http://www.easyhits4u.com/account.cgi"));

    request->setHeader(QNetworkRequest::ContentTypeHeader,"application/x-www-form-urlencoded");

    request->setRawHeader("Accept","image/gif, image/jpeg, image/pjpeg, image/pjpeg, application/x-shockwave-flash, application/x-ms-application, application/x-ms-xbap, application/vnd.ms-xpsdocument, application/xaml+xml, */*");

    request->setRawHeader("Referer","http://www.easyhits4u.com");

    request->setRawHeader("Accept-Language","zh-cn");

    request->setRawHeader("User-Agent","Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 2.0.50727; .NET CLR 3.0.04506.648; .NET CLR 3.5.21022; .NET4.0C; .NET4.0E)");

    request->setRawHeader("Content-Type","application/x-www-form-urlencoded");

    request->setRawHeader("Accept-Encoding","gzip,deflate");

    request->setRawHeader("Content-Length","94");

    request->setRawHeader("Connection","Keep-Alive");

    request->setRawHeader("Cache-Control","no-cache");



    reply = netWorkAcessM->post(*request,postData);

    connect(reply,SIGNAL(error(QNetworkReply::NetworkError)),this,SLOT(replyErrprSlot()));

点击按钮的时候我也用HttpAnalyze工具看了，没有问题的，可就是登陆不了，而且Post完毕后，也读取不到数据。

我把那个网站的首页保存下来，把没用的删掉，就剩下登陆框，输入账户密码也是可以登陆的。

保存下来修改过的网页内容



<!DOCTYPE html>

<html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://ogp.me/ns/fb#" xml:lang="en" lang="en" style="height: 100%; "><head><meta http-equiv="Content-Type" content="text/html; charset=UTF-8">

	<title>EasyHits4U.com - Your Traffic Exchange, 1:1 Exchange Ratio, Manual Surfing, Innovative Referral Program. FREE Traffic!</title>

</head>



<body style="position: relative; min-height: 100%; top: 0px; ">



<table cellpadding="0" cellspacing="0" border="0" valign="top" width="19%">

		<tbody><tr>

			<td width="235" valign="top" class="left_column">



<form action="http://www.easyhits4u.com/account.cgi" method="post">

	<input type="hidden" name="f" value="logon">

	<input type="hidden" name="manual" value="1">

	<input type="hidden" name="fb_id" value="">

	<input type="hidden" name="fb_token" value="">

	<!-- <input type="hidden" name="google_code" value=""> -->

	<div style="width:175px; padding-left:16px; padding-right:0px; font-size:11px; padding-top:8px; ">Username or Email:<br>

			<input type="text" name="username" size="30" class="login" value="" style="border: 1px solid rgb(109, 191, 109); "><br>

			

			Password:<br>

			<input type="password" name="password" class="login" value="" style="border: 1px solid rgb(109, 191, 109); "><br>

			<div align="center">

				<input type="image" src="./EasyHits4U.com - Your Traffic Exchange, 1 1 Exchange Ratio, Manual Surfing, Innovative Referral Program. FREE Traffic!_files/enter_btn.jpg" id="enter_btn" alt="Enter" title="Enter">

				

					<div id="fb-root"></div>

</div> 

		

	



	</div></form></td>

			

			</tr>

</tbody></table>

用webview调用我修改过的网页也是可以正常登陆的，但是自己模拟的post就是不行，大家看看我哪里出错了，有弄过的说过下

而且我发现post的信息中后面的x,y的数据每次都是不一样的，我在网页中也没有发现这个信息是怎么加进去的
f=logon&manual=1&fb_id=&fb_token=&google_code=&username=joke&password=qazwsxedc&x=7&y=5
我测试的时候就写死了，x7,y=5

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