String userName = request.getParameter("userName");
String password = request.getParameter("password");
PrintWriter writer = response.getWriter();
response.setCharacterEncoding("UTF-8");
if("123".equals(userName)&&"123".equals(password)){
writer.write("success:true,message:'successInfo'}");
}else{
writer.write("success:false,message:'failureInfo'}");
}
//String message=request.getParameter("message");
System.out.println("userName"+userName);
System.out.println("password"+password);
System.out.println("message"+message);
writer.close();
前台EXT：
buttons:[{
text:"提交",
handler:function(){
var basic=this.up("form").getForm();
var userName= basic.findField("userName")
var password= basic.findField("password")
basic.submit({
params:[{userName:userName},
{password:password}
],
url:'/Test/login.do?method=login',
method:'POST',
success:function(form,action){
//document.location="index.jsp";
Ext.Msg.alert("提示","成功："+action.result.message);
},
failure:function(form,action){
Ext.Msg.alert("提示","失败"+action.result.message);
}
});
}
}]
现在这的问题是火狐会报：Ext.Error: You're trying to decode an invalid JSON String: success:true,message:'successInfo'}
问题1：我应该怎么办才能让成功的时候执行成功的提示，失败的时候执行失败的提示呢？
问题2：这个是一个很简单的登录，如果我想让成功的时候跳转页面，不知道是在前台document.location 跳转，还是在后台跳转呢？
我是新手，还请大家多多帮助，尽可能的说的详细点，多谢大家了！！！
